A charged particle with initial kinetic energy of 80.3 keV ionizes an electron in the K shell of a silver atom. The binding energy for K-shell electrons in silver is 25.5 keV. The charged particle has kinetic energy of 43.7 keV after the interaction. What is the kinetic energy of the secondary electron, after it is ejected from the silver atom?
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- 3. A beam of helium-3 atoms (m = 3.016 u) is incident on a target of nitrogen-14 atoms (m = 14.003 u) at rest. Dur- ing the collision, a proton from the helium-3 nucleus passes to the nitrogen nucleus, so that following the col- lision there are two atoms: an atom of "heavy hydro- gen" (deuterium, m = 2.014 u) and an atom of oxygen-15 15.003 u). The incident helium atoms are moving at (m a velocity of 6.346 × 10° m/s. After the collision, the deu- terium atoms are observed to be moving forward (in the same direction as the initial helium atoms) with a velocity of 1.531 x 10' m/s. (a) What is the final velocity of the oxygen-15 atoms? (b) Compare the total kinetic energies before and after the collision.Particle Electron Proton Neutron Relative Charge -1 +1 0 What is: Electric Charge (C) -1.60 x 10-19 +1.60 x 10-19 0 a) The mass defect? Relative Mass (u) 5.485779 x 10-4 1.007276 1.008665 1u = 1.6605 x 10-27 kg 1eV = 1.60 x 10-19 Joules The 'cheating' equivalence shortcut 1u- 931.5 MeV He is the most abundant isotope of helium. Its mass is 6.6447x 10-27kg. Mass (kg) b) The binding energy of the nucleus in joules? 9.109390 x 10-31 1.672623 x 10-27 1.674929 x 10-274. In a hydrogen atom, the electron makes ω = 6×1015 rev/s (recall that this is the angular velocity) around the nucleus. We want to calculate how much current flows through a point in the orbit. (a) Calculate the time period of the orbit. Start by converting ω into rad/s. (b) Use the definition of current to calculate I due to the revolution of the electron around the nucleus.
- I need help trying to figgure out how to fill out the graph by just using the info on the graphA positron and an electron with negligible kinetic energy meet and annihilate one another, producing two y-rays of equal energy. the wavelength of these y-rays is ..···. O 2.428 pm O 14.28 Á O 4.822 pm O 1.428 pmRobert Millikan was an American physicist who in 1909 performed a classic experiment involving charged oil drops. Millikan adjusted the voltage applied between two metal plates in order to suspend charged drops in the resulting electric field. For a suspended drop, the electrostatic force directed up exactly balances out the weight of the drop. Millikan ultimately determined the charge on an electron and that charge is quantized. This means that charge comes in increments, discrete amounts, rather than any amount.A NEGATIVELY-charged oil drop is suspended between two plates of opposite charge by an electric field of 603 newtons per coulomb. The drop is determined to have a mass of 8.86 x 10-17 kilograms. a. What is the charge on the drop? Include units in your answer.
- What two pieces of evidence allowed the first calculation of me , the mass of the electron?(a) The ratios qe / me and q p / m p .(b) The values of qe and EB .(c) The ratio qe / me and qe .Justify your response.Assume a hypothetical atom with a nucleus that consists of two positrons (instead of two protons). Positron has a charge of +1 and the mass of an electron. Write down the hydrogen like energy of a neutral 2-positrons atom.A proton of energy 25 MeV is moving in Pb. How much energy does it lose in a collision with an alpha particle? How many collisions are required to completely stop it?