A charge q = -3Q rests inside a pyramid as shown in the figure below. The pyramid has a lateral base perimeter of a units and a lateral base height of b units. What is the total electric flux through the pyramid? (a) O = - kQ/b² (b) 0 = - 3 Q/ɛn (c) 0 = -3Q2²/b² ɛo (d) 0 = -3Qa² b² / ɛo (e) 0 = -6 kQ/b a² -за

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A charge q = -3Q rests inside a pyramid as shown in the figure below. The pyramid has a
lateral base perimeter of a units and a lateral base height of b units. What is the total
electric flux through the pyramid?
(a) 0 = - kQ/b²
(b) 0 = - 3 Q/ɛn
(c) 0 = -3Q2²/b² ɛo
(d) 0 = -3Qa? b²/ ɛ0
(е) Ф% -6 ka/b а?
-за
Transcribed Image Text:A charge q = -3Q rests inside a pyramid as shown in the figure below. The pyramid has a lateral base perimeter of a units and a lateral base height of b units. What is the total electric flux through the pyramid? (a) 0 = - kQ/b² (b) 0 = - 3 Q/ɛn (c) 0 = -3Q2²/b² ɛo (d) 0 = -3Qa? b²/ ɛ0 (е) Ф% -6 ka/b а? -за
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