A charge q = 1 μC is located at the tip of a hollow cone (such as an ice cream cone without the ice cream) with surface charge density o = 6.4 μC/m². The slant height of the cone is L = 4 mm, and the half-angle at the vertex is 10⁰. = L12 L/2 If the top half of the cone is removed and thrown away, what is the force (in Newton's) on the charge 9 due to the remaining part of the cone?
A charge q = 1 μC is located at the tip of a hollow cone (such as an ice cream cone without the ice cream) with surface charge density o = 6.4 μC/m². The slant height of the cone is L = 4 mm, and the half-angle at the vertex is 10⁰. = L12 L/2 If the top half of the cone is removed and thrown away, what is the force (in Newton's) on the charge 9 due to the remaining part of the cone?
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![A charge q = 1 μC is located at the tip of a hollow
cone (such as an ice cream cone without the ice
cream) with surface charge density o = 6.4 μC/m².
The slant height of the cone is L = 4 mm, and the
half-angle at the vertex is 0: 10⁰.
=
L12
L/2
If the top half of the cone is removed and thrown
away, what is the force (in Newton's) on the charge
9 due to the remaining part of the cone?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F03aedc64-180e-4d6f-8ab9-cfdbd777be5c%2Fb11e0748-2e74-43ad-b36b-91cf98278cda%2Fvc7wss_processed.png&w=3840&q=75)
Transcribed Image Text:A charge q = 1 μC is located at the tip of a hollow
cone (such as an ice cream cone without the ice
cream) with surface charge density o = 6.4 μC/m².
The slant height of the cone is L = 4 mm, and the
half-angle at the vertex is 0: 10⁰.
=
L12
L/2
If the top half of the cone is removed and thrown
away, what is the force (in Newton's) on the charge
9 due to the remaining part of the cone?
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