A charge of -8.41 µC is traveling at a speed of 8.16 x 10° m/s in a region of space where there is a magnetic field. The angle between the velocity of the charge and the field is 54.7°. A force of magnitude5.25 x 103 N acts on the charge. What is the magnitude of the magnetic field?
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- A proton travels with a speed of (7.0x10^4) m/s along the x-axis. A uniform magnetic field of strength (1.290x10^-3) T directed along the y-axis is turned on, and the proton starts travelling in a circle due to the magnetic force. What is the radius of this circle? Give your answer in meters (m) using scientific notation.A particle with charge 1.53 x 10^-6 C moves at 2.44 x 10^6 m/s through a magnetic field of strength 2.13 T. The angle between the particle s velocity and the magnetic field direction is 31.3 degrees and the particle undergoes an acceleration of 11.3 m/s^2. What is the particle s mass? 9.0 kg 15.8 kg 0.37 kg 4.5 kgA proton moving at 5.50 x 106 m/s through a magnetic field of magnitude 1.77 T experiences a magnetic force of magnitude 7.30 × 10-13 N. What is the angle between the proton's velocity and the field? Step 1 The magnitude of the force on a moving charge in a magnetic field is FB = qvB sin 8, and, solving for the angle, we have the following. 8 sin -1 = sin-¹ B qvB 1.60 x 10-19 c)([ x 10-13 N |× 106 m/s) (
- A charge of -8.84 μC is traveling at a speed of 6.02 × 106 m/s in a region of space where there is a magnetic field. The angle between the velocity of the charge and the field is 55.1o. A force of magnitude6.02 × 10-3 N acts on the charge. What is the magnitude of the magnetic field?A very long straight wire carries a current of 3.5A from left to right in the plane of this screen. An electron with a charge of −1.6×10−19C is moving from left to right at a point that is 3.5cm above the wire. Its speed is 2.5×105m/s. What is the magnitude and direction of the magnetic force that the electron experiences due to the presence of this current-carrying wire? The permeability of free space is μ0=4π×10−7T⋅m/A.Here the charge is 3.09 x 10^-6 C, the magnetic field strength is 1.03 T and the electric field strength is 1.05 x 10^5 N/C. The charge experiences a total force of magnitude 16.00 N as it enters the region. What is its speed as it enters the region? 8.38E+06 m/s 4.93E+06 m/s 3.45E+06 m/s 5.92E+06 m/s
- A particle with a charge of 0.9 C is moving at right angles to a uniform magnetic field with a strength of 0.4 T. The velocity of the charge is 700 m/s. What is the magnitude of the magnetic force exerted on the particle?A particle with charge 7.30 x 10^-6 C moves at 3.00 x 10^6 m/s through a magnetic field of strength 2.52 T. The angle between the particles velocity and the magnetic field direction is 53.0 degrees and the particle undergoes an acceleration of 6.8 m/s^2. What is the particles mass? 6.48 kg 2.7 kg 5.4 kg 8.8 kgA charge is moving perpendicular to a magnetic field and experiences a force whose magnitude is 1.33 × 10-3 N. If this same charge were to move at the same speed and the angle between its velocity and the same magnetic field were 26.9o, what would be the magnitude of the magnetic force that the charge would experience?
- An proton moving at 2.00 x 10³ m/s and at an angle of 53° to a magnetic field experiences a magnetic force of 7.4 x 1016 N. What is the magnitude of the magnetic field? q, = 1.60x10-19 C. Provide the solution:A magnetic field has a magnitude of 0.00090 T, and an electric field has a magnitude of 4.1 x 103 N/C. Both fields point in the same direction. A positive 2.1-µC charge moves at a speed of 2.5 x 106 m/s in a direction that is perpendicular to both fields. Determine the magnitude of the net force that acts on the charge. Number MI Units B HI 90°A particle with a charge of q = - 1.24 × 10-8 ℃ is moving with instantaneous velocity V = 1.42 x 104 m/si +3.85 x 104 m/sĵ. What is the force exerted on this particle by a magnetic field: a) B = 11.4 TÎ and b) B = 11.4Tk?