A charge of 2q is placed at the origin and a second charge of +q is placed at x = 5.0 cm. Where can a third charge +q be placed so that it experiences a force of zero? [A5]

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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P2 Answer 5
SPH4U9: Fields Take-Home Assignment
Name:
5. A charge of 2q is placed at the origin and a second charge of +q is placed at x = 5.0 cm. Where can a third
charge +q be placed so that it experiences a force of zero? [A5]
6. Six point charges of equal magnitude Q are held at the corners of a hexagon with the signs of the charges as
shown. Each side of the hexagon has length 'a', and 'P' is at the centre of the hexagon.
a
a) Derive the formula for the electric field strength at point P due to ONE
point charge. No directions are necessary for this question. [T2]
-Q
+Q
0
b) Draw the arrows to represent the direction of the field at P due to point
charge A and point charge B. [T1]
c) If the magnitude of Q is 2.6 µC and the length 'a' is 0.12 m, determine
the magnitude and the direction of the electric field strength at point P
due to all six charges. [T5]
a
8. An electron with a horizontal speed of 4.7 x 106 m/s passes through two horizontal plates, as shown below. The
magnitude of the electric field between the plates is 150 N/C. The plates are 8.5 cm long.
a. Calculate the vertical component of the electron's final velocity [T5]
b. Calculate the final velocity of the electron. [T3]
+++++
e
X
+QQ
A
B
-Q
●P
-Q
P+Q
Transcribed Image Text:SPH4U9: Fields Take-Home Assignment Name: 5. A charge of 2q is placed at the origin and a second charge of +q is placed at x = 5.0 cm. Where can a third charge +q be placed so that it experiences a force of zero? [A5] 6. Six point charges of equal magnitude Q are held at the corners of a hexagon with the signs of the charges as shown. Each side of the hexagon has length 'a', and 'P' is at the centre of the hexagon. a a) Derive the formula for the electric field strength at point P due to ONE point charge. No directions are necessary for this question. [T2] -Q +Q 0 b) Draw the arrows to represent the direction of the field at P due to point charge A and point charge B. [T1] c) If the magnitude of Q is 2.6 µC and the length 'a' is 0.12 m, determine the magnitude and the direction of the electric field strength at point P due to all six charges. [T5] a 8. An electron with a horizontal speed of 4.7 x 106 m/s passes through two horizontal plates, as shown below. The magnitude of the electric field between the plates is 150 N/C. The plates are 8.5 cm long. a. Calculate the vertical component of the electron's final velocity [T5] b. Calculate the final velocity of the electron. [T3] +++++ e X +QQ A B -Q ●P -Q P+Q
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