A Channel C6x13 is used as a tension member. The holes are for 5/8 inch in diameter of bolts. Using A36 steel with Fy=36 ksi and Fu=58 ksi. The gross area of C6x13 is 3.81 in2 and Assume U =0.85 Using LRFD what is the design strength based on Tensile Rupture/Fracture

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A: Hi! Thank you for the question As per the honor code, We’ll answer the first question since the…

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Q: F1 lb F2 Ib/ft F3 Ib/ft A B| D E 3 ft 6 ft 9 ft 3 ft 9 ft F1= 12, F2 = 15, F3 = 21 Derive the shear…

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Q: Hello, can i get help in solving this exercise?

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Q: a) Draw the influence line for the bending moment at point C b) Determine the maximum positive and…

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Q: Determine the maximum shearing stress of the beam shown in the above problem (prob. #2) 5 kN 2 m 2.5…

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Fluid Materials

In general terms, anything that flows can be termed as a fluid. In other words, a fluid is any substance that cannot resist shear forces and deforms continuously under the application of external shear forces. Fluid materials differ completely from solid materials such as metals and alloys. For instance, if we consider two infinitesimally small cross-sectional areas of fluid materials and solid materials, and apply shear forces to these elements, both the elements will undergo deformation. Upon releasing the shear force, the element of the solid materials will regain its original orientation, but the element of the fluid materials will keep on deforming continuously under the action of the shear force.