(a) Change the right-hand sides to b₁ [20] 30
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
Answer only a)
Note:
I Leave an attached image with the solution, for you to confirm the correct answer.

Transcribed Image Text:(a)
Abj = -10, Ab2 = 20
-10
+ AZ* = (0 2)
= 40
20
Al; = (1 -1))
-30
20
–10
Ab, = (0 1)
= 20
20
Revised Final Tableau:
Bas | Eq|
Var | No| Z|
Coefficient of
| Right
X1
x2 X3
X4
X5
side
Z| 01 1|
X4| 1| 01
X1| 2| 01
1
1
60
-1
5
1
-1
-10
1
4
-1
30
The current basic solution is superoptimal, but infeasible.
Revised Final Tableau After Reoptimization (Dual Simplex Method) :
Bas | Eq|
Var | No| Z|
| Right
X5
Coefficient of
X1
x2 X3
X4
side
Z| 01 1|0.333
X2| 1| 010.333
X5| 2| 01-0.33
O 12.33 2.333
1 1.333 0.333
O -6.33 -1.33
| 46.67
| 6.667
| 3.333
1.

Transcribed Image Text:DI 6.7-4. Consider the following problem.
Мaximize
Z = 2x1 + 7x2 – 3x3,
subject to
x1 + 3x2 + 4xz < 30
X1 + 4x2
X3 < 10
-
and
x¡ 2 0,
x2 2 0,
Xz 2 (0.
By letting x4 and x5 be the slack variables for the respective con-
straints, the simplex method yields the following final set of
equations:
+ 2x5 = 20
X5 = 20
+ x5 = 10.
z + x2 + X3
(0)
(1)
(2)
x2 + 5x3 + x4 –
X1 + 4x2 - X3
Now you are to conduct sensitivity analysis by independently in-
vestigating each of the following seven changes in the original
model. For each change, use the sensitivity analysis procedure to
revise this set of equations (in tableau form) and convert it to
proper form from Gaussian elimination for identifying and eval-
uating the current basic solution. Then test this solution for fea-
sibility and for optimality. If either test fails, reoptimize to find a
new optimal solution.
(a) Change the right-hand sides to
Г20
b2
(30
(b) Change the coefficients of x3 to
C3
-27
a13
a23.
3.
||
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