A certain weak base has a K, of 7.20 × 10-7. What concentration of this base will produce a pH of 10.14? concentration:

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Chapter16: Acid-base Equilibria
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Problem 16.137QP
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A certain weak base has a K, of 7.20 × 10-7. What concentration of this base will produce a pH of 10.14?
concentration:
Transcribed Image Text:A certain weak base has a K, of 7.20 × 10-7. What concentration of this base will produce a pH of 10.14? concentration:
Expert Solution
Step 1

Given 

  • Kb = 7.20 x 10-7
  • pH = 10.14 

we know 

pH + pOH = 14 

pOH = 14 - 10.14 = 3.86

and   [OH-] = 10-pOH

[OH-] = 10-3.86 = 1.5 x 10-4 M

 

Let the weak base be B .

The balanced chemical reaction is - 

B(aq) + H2O(l)  BH+(aq) + OH-(aq) 

The equilibrium constant expression is given by -

Kb =[BH+] [OH-][B] ------------(1) 

[BH+] = [OH-] = 1.5 x 10-4 M

Substitute all the known values in the equation (1), 

7.20 × 10-7 = (1.5× 10-4)2[B][B] = (1.5 × 10-4)27.20 × 10-7[B] = 2.25 × 10-87.20 × 10-7[B] = 0.03125 M

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