A certain Volkswagen Beetle is air-tight, so that when the doors are closed and the windows rolled up, no air can escape or enter. Suppose the car is parked with its doors closed and the interior air at an initial pressure of 1.00 atmosphere, and the initial temperature Ti = 22,0° C. Later, due to the greenhouse effect, the temperature rises to T2 = 52° C. What will be the air pressure inside the car?

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
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## Temperature Conversions and Thermal Expansion Concepts

### Temperature Conversion Formulas
1. **Celsius to Kelvin:**
   \[
   T_C = T_K - 273^\circ C
   \]

2. **Celsius to Fahrenheit:**
   \[
   T_F = \frac{9}{5}T_C + 32
   \]

3. **Fahrenheit to Celsius:**
   \[
   T_C = \frac{5}{9}(T_F - 32)
   \]

### Thermal Expansion
1. **Linear Expansion:** 
   \[
   \Delta L = \alpha L_0 \Delta T
   \]

2. **Area Expansion:**
   \[
   \Delta A = \gamma A_0 \Delta T \quad \gamma = 2\alpha
   \]

3. **Volume Expansion:**
   \[
   \Delta V = \beta V_0 \Delta T \quad \beta = 3\alpha
   \]

### Gas Laws and Kinetic Theory
1. **Ideal Gas Law:**
   \[
   PV = nRT
   \]
   - \( P \): Pressure
   - \( V \): Volume
   - \( n \): Number of moles
   - \( R \): Universal gas constant (8.31 J/mole-K)
   - \( T \): Temperature in Kelvin

2. **Combined Gas Law:**
   \[
   \frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}
   \]

3. **Kinetic Energy of Gas Particles:**
   \[
   \frac{1}{2} mv^2 = \frac{3}{2} k_B T
   \]
   - \( m \): Mass of a particle
   - \( v \): Velocity of a particle
   - \( k_B \): Boltzmann’s constant (\(1.38 \times 10^{-23}\) J/K)
   - \( T \): Temperature in Kelvin

### Constants
- **Number of Moles Calculation:**
  \[
  \text{Number of moles, } n = \frac{\text{mass (grams)}}{\text{molecular weight}}
  \]

- **Avogadro's Number:**
  \[
  N_A =
Transcribed Image Text:## Temperature Conversions and Thermal Expansion Concepts ### Temperature Conversion Formulas 1. **Celsius to Kelvin:** \[ T_C = T_K - 273^\circ C \] 2. **Celsius to Fahrenheit:** \[ T_F = \frac{9}{5}T_C + 32 \] 3. **Fahrenheit to Celsius:** \[ T_C = \frac{5}{9}(T_F - 32) \] ### Thermal Expansion 1. **Linear Expansion:** \[ \Delta L = \alpha L_0 \Delta T \] 2. **Area Expansion:** \[ \Delta A = \gamma A_0 \Delta T \quad \gamma = 2\alpha \] 3. **Volume Expansion:** \[ \Delta V = \beta V_0 \Delta T \quad \beta = 3\alpha \] ### Gas Laws and Kinetic Theory 1. **Ideal Gas Law:** \[ PV = nRT \] - \( P \): Pressure - \( V \): Volume - \( n \): Number of moles - \( R \): Universal gas constant (8.31 J/mole-K) - \( T \): Temperature in Kelvin 2. **Combined Gas Law:** \[ \frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2} \] 3. **Kinetic Energy of Gas Particles:** \[ \frac{1}{2} mv^2 = \frac{3}{2} k_B T \] - \( m \): Mass of a particle - \( v \): Velocity of a particle - \( k_B \): Boltzmann’s constant (\(1.38 \times 10^{-23}\) J/K) - \( T \): Temperature in Kelvin ### Constants - **Number of Moles Calculation:** \[ \text{Number of moles, } n = \frac{\text{mass (grams)}}{\text{molecular weight}} \] - **Avogadro's Number:** \[ N_A =
**Problem: Calculating Air Pressure Inside a Sealed Car**

A certain Volkswagen Beetle is air-tight, so that when the doors are closed and the windows rolled up, no air can escape or enter. Suppose the car is parked with its doors closed and the interior air at an initial pressure of 1.00 atmosphere, and the initial temperature \( T_1 = 22^\circ \text{C} \). Later, due to the greenhouse effect, the temperature rises to \( T_2 = 52^\circ \text{C} \). What will be the air pressure inside the car?

---

**Explanation:**

- This problem involves understanding how temperature changes affect air pressure in a confined space, applying principles of thermodynamics.
- You can use the ideal gas law to solve this, assuming the quantity of air and the volume of the car remain constant.
  
Steps:
1. Convert temperatures from Celsius to Kelvin by adding 273.15.
2. Use the formula: \( P_1/T_1 = P_2/T_2 \) to find the new pressure \( P_2 \).

There are no graphs or diagrams included in the original text.
Transcribed Image Text:**Problem: Calculating Air Pressure Inside a Sealed Car** A certain Volkswagen Beetle is air-tight, so that when the doors are closed and the windows rolled up, no air can escape or enter. Suppose the car is parked with its doors closed and the interior air at an initial pressure of 1.00 atmosphere, and the initial temperature \( T_1 = 22^\circ \text{C} \). Later, due to the greenhouse effect, the temperature rises to \( T_2 = 52^\circ \text{C} \). What will be the air pressure inside the car? --- **Explanation:** - This problem involves understanding how temperature changes affect air pressure in a confined space, applying principles of thermodynamics. - You can use the ideal gas law to solve this, assuming the quantity of air and the volume of the car remain constant. Steps: 1. Convert temperatures from Celsius to Kelvin by adding 273.15. 2. Use the formula: \( P_1/T_1 = P_2/T_2 \) to find the new pressure \( P_2 \). There are no graphs or diagrams included in the original text.
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