A certain triple-star system consists of two stars, each of mass m = 4.8x1030 kg, revolving in the same circular orbit of radius r = 3.2x1011 m about a central star of mass M = 6.9x1053 kg (the figure). The two orbiting stars are always at opposite ends of a diameter of the orbit. Calculate the period of revolution of the stars. Number Units the tolerance is +/-2% Click if you would like to Show Work for this question: Open Show Work

College Physics
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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
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Chapter 13, Problem 079
A certain triple-star system consists of two stars, each of mass m = 4.8×1030 kg, revolving in the same circular orbit of radius r = 3.2x1011 m about a central star of mass
M = 6.9x1033 kg (the figure). The two orbiting stars are always at opposite ends of a diameter of the orbit. Calculate the period of revolution of the stars.
Number
Units
the tolerance is +/-2%
Click if you would like to Show Work for this question: Open Show Work
Transcribed Image Text:PRINTER VERSION 4 ВАСК NEXT Chapter 13, Problem 079 A certain triple-star system consists of two stars, each of mass m = 4.8×1030 kg, revolving in the same circular orbit of radius r = 3.2x1011 m about a central star of mass M = 6.9x1033 kg (the figure). The two orbiting stars are always at opposite ends of a diameter of the orbit. Calculate the period of revolution of the stars. Number Units the tolerance is +/-2% Click if you would like to Show Work for this question: Open Show Work
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