A certain spring is used as a scale to find the weight of groceries. When you place exactly 1.0-kg of bananas on the spring and let them come to rest, it compresses 2.3-cm. When you place a watermelon of unknown mass on the spring and let it come to rest, it compresses 6.2-cm. A. Draw a free-body diagram for each case. B. Find the spring constant of the spring. k = 427 N/m C. Determine the mass of the watermelon. mw = 2.7 kg

College Physics
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Chapter1: Units, Trigonometry. And Vectors
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**Problem 3**

A certain spring is used as a scale to find the weight of groceries. When you place exactly 1.0-kg of bananas on the spring and let them come to rest, it compresses 2.3 cm. When you place a watermelon of unknown mass on the spring and let it come to rest, it compresses 6.2 cm.

A. Draw a free-body diagram for each case.

B. Find the spring constant of the spring. \( k = 427 \, \text{N/m} \)

C. Determine the mass of the watermelon. \( m_w = 2.7 \, \text{kg} \)
Transcribed Image Text:**Problem 3** A certain spring is used as a scale to find the weight of groceries. When you place exactly 1.0-kg of bananas on the spring and let them come to rest, it compresses 2.3 cm. When you place a watermelon of unknown mass on the spring and let it come to rest, it compresses 6.2 cm. A. Draw a free-body diagram for each case. B. Find the spring constant of the spring. \( k = 427 \, \text{N/m} \) C. Determine the mass of the watermelon. \( m_w = 2.7 \, \text{kg} \)
### Newton's Laws and Energy Concepts

**Newton's Second Law and Momentum:**

\[
\Sigma \vec{F}_{\text{on obj}} = \frac{d\vec{p}_{\text{obj}}}{dt} = m_{\text{obj}} \vec{a}_{\text{obj}}
\]

- This equation represents Newton's second law in terms of momentum, where the net force on an object is equal to the derivative of its momentum over time, or the product of mass and acceleration.

**Gravitational and Spring Forces:**

\[
F^{G}_{E0} = m_0 g
\]

- The gravitational force on an object is represented by the product of its mass and the acceleration due to gravity.

\[
F^{C}_{S0} = k \Delta x
\]

- The force exerted by a spring is proportional to its displacement, where \( k \) is the spring constant.

**Work Done by a Force:**

\[
W_F = \int_{x_i}^{x_f} |\vec{F}| \cos \theta \, |d\vec{x}|
\]

- Work done by a force is the integral of the force along the path of displacement, considering the angle between force and displacement.

\[
W_F = |\vec{F}| \cos \theta |\Delta \vec{x}|
\]

- For constant forces, work can be simplified as the product of the force magnitude, the cosine of the angle between the force and displacement directions, and the magnitude of displacement.

**Friction and Thermal Energy:**

- If friction is present: \(\Delta E_{\text{th}} = |\vec{F}_{\text{friction}}| |\Delta \vec{x}|\)

  - The thermal energy increase is due to the frictional force times the displacement.

**Conservation of Energy:**

\[
\Sigma E_{n,i} + W_{\text{ext}} = \Sigma E_{n,f}
\]

- The total initial energy plus external work equals the total final energy.

OR

\[
E_{\text{Mech},i} + W_{\text{ext}} = E_{\text{Mech},f} + \Delta E_{\text{Int}}
\]

- The initial mechanical energy plus work done by external forces equals the final mechanical energy plus internal energy changes.

**Mechanical Energy:**

\[
Transcribed Image Text:### Newton's Laws and Energy Concepts **Newton's Second Law and Momentum:** \[ \Sigma \vec{F}_{\text{on obj}} = \frac{d\vec{p}_{\text{obj}}}{dt} = m_{\text{obj}} \vec{a}_{\text{obj}} \] - This equation represents Newton's second law in terms of momentum, where the net force on an object is equal to the derivative of its momentum over time, or the product of mass and acceleration. **Gravitational and Spring Forces:** \[ F^{G}_{E0} = m_0 g \] - The gravitational force on an object is represented by the product of its mass and the acceleration due to gravity. \[ F^{C}_{S0} = k \Delta x \] - The force exerted by a spring is proportional to its displacement, where \( k \) is the spring constant. **Work Done by a Force:** \[ W_F = \int_{x_i}^{x_f} |\vec{F}| \cos \theta \, |d\vec{x}| \] - Work done by a force is the integral of the force along the path of displacement, considering the angle between force and displacement. \[ W_F = |\vec{F}| \cos \theta |\Delta \vec{x}| \] - For constant forces, work can be simplified as the product of the force magnitude, the cosine of the angle between the force and displacement directions, and the magnitude of displacement. **Friction and Thermal Energy:** - If friction is present: \(\Delta E_{\text{th}} = |\vec{F}_{\text{friction}}| |\Delta \vec{x}|\) - The thermal energy increase is due to the frictional force times the displacement. **Conservation of Energy:** \[ \Sigma E_{n,i} + W_{\text{ext}} = \Sigma E_{n,f} \] - The total initial energy plus external work equals the total final energy. OR \[ E_{\text{Mech},i} + W_{\text{ext}} = E_{\text{Mech},f} + \Delta E_{\text{Int}} \] - The initial mechanical energy plus work done by external forces equals the final mechanical energy plus internal energy changes. **Mechanical Energy:** \[
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