A certain model phone costs $599. The probability of the phone breaking over the course of a year is .07. What is the maximum amount you could pay for phone replacement insurance and still have a non-negative expected value on the policy? In other words, for what price or below would it be worth it to get the insurance?

MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
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Chapter1: Starting With Matlab
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A certain model phone costs $599. The probability of the phone breaking over the course of a year is .07.
What is the maximum amount you could pay for phone replacement insurance and still have a non-negative
expected value on the policy? In other words, for what price or below would it be worth it to get the
insurance?
Transcribed Image Text:A certain model phone costs $599. The probability of the phone breaking over the course of a year is .07. What is the maximum amount you could pay for phone replacement insurance and still have a non-negative expected value on the policy? In other words, for what price or below would it be worth it to get the insurance?
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From the given information, a certain model phone costs $599. The probability of the phone breaking over the course of a year is 0.07.

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