A certain indicator, HA, has a K₂ value of 4.0 x 10-7. The protonated form of the indicator is blue and the ionized form is red. What is the pKa of the indicator? pK₂ = What is the color of this indicator in a solution with pH = 4? red purple blue
A certain indicator, HA, has a K₂ value of 4.0 x 10-7. The protonated form of the indicator is blue and the ionized form is red. What is the pKa of the indicator? pK₂ = What is the color of this indicator in a solution with pH = 4? red purple blue
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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
Transcribed Image Text:### Understanding Indicators and pKa
**Problem Statement:**
A certain indicator, HA, has a \( K_a \) value of \( 4.0 \times 10^{-7} \). The protonated form of the indicator is blue, and the ionized form is red.
1. **Question**: What is the \( pK_a \) of the indicator?
- **Answer Box**: (space provided)
2. **Question**: What is the color of this indicator in a solution with \( \text{pH} = 4 \)?
- **Options**:
- ☐ red
- ☐ purple
- ☐ blue
---
### Explanation:
- **Calculating pKa**:
The \( pK_a \) is calculated using the formula \( pK_a = -\log(K_a) \).
- **Color Indication**:
- The color of an indicator in solution is based on the pH compared to its \( pK_a \).
- If the pH is lower than the \( pK_a \), the solution is likely dominated by the **protonated form (blue)**.
- If the pH is higher, the **ionized form (red)** is predominant.
In this case, with \( pH = 4 \), you would compare it to the calculated \( pK_a \) to determine the color.
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