A certain exoplanet has a radius of 8.00x10³ kilometers and a mass of 6.4x1024 kg. A simple pendulum (consisting of a lead weight of mass 500 grams, and a thin string) of length 2.00 m is set up on the surface of this planet. The period of this pendulum is 1.82 s 0.548 s 0.291 s 3.44 s O 2.84 s

Q: A simple pendulum of mass m = 2.00 kg and length L = 0.82 m on planet X, where the value of g is…

A: m= 2 kg L =0.82 m T =1.70 s

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Q: A simple pendulum of mass m = 2.00 kg and length L = 0.82 m on planet X, where the value of g is…

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A: as per our guidelines we are supposed to answer only one question. Kindly repost other questions as…

Q: A simple pendulum of mass m = 2.00 kg and length L = 0.82 m on planet X, where the value of g is…

A:

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Q: What is the length of second's pendulum? O 1.5 m 2 m 99.3 cm 98.5 cm

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Proper Length

The theory of special relativity explains the connection between space and time to objects that move in a straight line at a constant speed. The objects move at the speed of light. When an object approaches light speed, its mass is endless and cannot move faster than light. The most crucial postulate of Einstein's special relativity is that the laws of nature do not change in each frame of reference.