**Clinical Trial Analysis of Asthma Drug**In a clinical trial for a specific asthma medication, 22 out of 272 treated subjects reported experiencing headaches. This analysis explores the claim that less than 11% of treated subjects experienced headaches, using the normal distribution as an approximation to the binomial distribution. We will conduct a hypothesis test with a significance level of 0.05 to evaluate this claim.**Test Components:**1. **Tail of the Test:** - Is the test two-tailed, left-tailed, or right-tailed? - Right-tailed test - Two-tailed test - **Left-tailed test (Selected)**2. **Test Statistic:** - The test statistic, denoted as $ z $, is calculated as: - $ z = -1.53 $ - (Rounded to two decimal places as needed)3. **P-Value:** - The P-value is yet to be determined (Round to four decimal places as needed).**Calculator Display Summary:**- **1-PropZTest Summary:** - $ \text{prop} < 0.11 $ - $ z = -1.534791494 $ - $ p = 0.06241735264 $ (Preliminary P-value) - $ \hat{p} = 0.0808823529 $ (Sample proportion) - $ n = 272 $This data allows students to analyze the hypothesis test structure, understand the implications of the test statistic value, and interpret the P-value for decision-making regarding the hypothesis.

a) The claim of the test is p<0.11.

Answered: A certain drug is used to treat asthma.…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A researcher takes sample temperatures in Fahrenheit of 17 days from New York City and 18 days from Phoenix. Test the claim that the mean temperature in New York City is different from the mean temperature in Phoenix. Use a significance level of α=0.05. Assume the populations are approximately normally distributed with unequal variances. You obtain the following two samples of data. New York City Phoenix 99 94.2 95.5 72 93.2 86.8 102 122.1 85.4 114.4 80 94.7 86.4 89.7 75.4 104.7 79.5 77.6 83.4 106.8 64.3 98.6 65.5 91.5 87.7 82 104 97.7 74.3 64.9 59.5 82 82.8 72 116.2 The Hypotheses for this problem are: H0: μ1 = μ2 H1: μ1μ2 Find the p-value. Round answer to 4 decimal places. Make sure you put the 0 in front of the decimal. p-value =
A firm produces calculators. It manager claims that its calculators are good, on average, for at least 58 months. A consumer protection agency tested 16 such calculators to check this claim. He found the mean life of these calculators to be 55 months with a variance of 9 months. Can you conclude that the claim of this company is true? Use a = 0.05. Assume that the life of such a calculator has an approximately normal distribution. According to this information the null and alternative hypotheses are: H0: μ ≤ 58 H1: μ > 58 Select one: True False
Choose the appropriate statistical test. When computing, be sure to round each answer as indicated. A dentist wonders if depression affects ratings of tooth pain. In the general population, using a scale of 1-10 with higher values indicating more pain, the average pain rating for patients with toothaches is 6.8. A sample of 30 patients that show high levels of depression have an average pain rating of 7.1 (variance 0.8). What should the dentist determine? 1. Calculate the estimated standard error. (round to 3 decimals). [st.error] 2. What is thet-obtained? (round to 3 decimals). 3. What is the t-cv? (exact value) 4. What is your conclusion? Only type "Reject" or Retain"
You conduct a between-subjects ANOVA investigating whether different states produce tastier cheeses. You find that eta-squared is .50. What does this tell you? a. The effect size is small. b. 50% of the total variance in tastiness is due to differences between the states. c. The difference between the group means is .50 standard deviations. d. All of the above
what is z score and p value?
A random sample of 40 college students has a mean earnings of $3120 with a standard deviation of $677 over the summer months. Determine whether a normal distribution or a t-distribution should be used or whether neither of these can be used to construct a confidence interval. Question 2 options: Cannot use normal distribution or t-distribution. Use normal distribution. Use the t-distribution.
The average score on a statistics test was 2.21 with a standard deviation of 0.88. The teacher suspects that the exam was very difficult; Based on the above, you want to adjust the scores so that the mean is 3.37 and the standard deviation is 0.25. Compute the values a and b such that the fit of type aX+b gives the desired mean and variance? Calculate: a= Answer b= Answer TIP: Use expected value and variance properties.
A group of students (large group) took a test in mathematics and the final scores have a mean of 68 and a variance of 100. If the distribution of these scores is approximately normal, then what percent of the students: i. Scored higher than 75? Should pass the test (scores > 65)? Should fail the test (scores < 65)? ii. iii.
HYPERTENSION. The data below was collected from over 200 infants at 1 month of age. In this study a research nurse visited the home of each child and took their blood pressure using a special apparatus for measuring infant bp. She also noted whether the infant was asleep or awake and whether or not the child was agitated when the bp was taken. Assuming equal variances, is there a significant mean difference in SBP between the quiet sleep infants and the awake and quiet infants? 1. What is the appropriate test to conduct in the above situation? 2. What is the degree of freedom? 3. What is the computed test statistic? 4. What is the correct conclusion for this test? 5. What can be implied from the conclusion above?
Women are recommended to consume 1700 calories per day. You suspect that the average calorie intake is different for women at your college. The data for the 12 women who participated in the study is shown below: 1808, 1681, 1723, 1847, 1808, 1858, 1461, 1449, 1631, 1635, 1815, 1874 Assuming that the distribution is normal, what can be concluded at the αα = 0.01 level of significance? For this study, we should use The null and alternative hypotheses would be: H0:H0: H1:H1: The test statistic = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is αα Based on this, we should the null hypothesis. Thus, the final conclusion is that ... The data suggest the population mean is not significantly different from 1700 at αα = 0.01, so there is sufficient evidence to conclude that the population mean calorie intake for women at your college is equal to 1700. The data…
Refer to the below table. Using an alpha = 0.05, test the claim that IQ scores are the same for children in three different blood lead level groups: low lead level, medium lead level, and high lead level). One-Way Analysis of Variance Summary Table for IQ Measurements for Children among Three Blood Lead Level Groups: Low Lead Level, Medium Lead Level, and High Lead Level. Source df SS MS F p Between-group (treatment) 2 469.1827 2677.864 2.30 0.104 Within-group (error) 118 203.6918 11745.05 Total 120

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