**Clinical Trial Analysis of Asthma Drug**In a clinical trial for a specific asthma medication, 22 out of 272 treated subjects reported experiencing headaches. This analysis explores the claim that less than 11% of treated subjects experienced headaches, using the normal distribution as an approximation to the binomial distribution. We will conduct a hypothesis test with a significance level of 0.05 to evaluate this claim.**Test Components:**1. **Tail of the Test:** - Is the test two-tailed, left-tailed, or right-tailed? - Right-tailed test - Two-tailed test - **Left-tailed test (Selected)**2. **Test Statistic:** - The test statistic, denoted as \( z \), is calculated as: - \( z = -1.53 \) - (Rounded to two decimal places as needed)3. **P-Value:** - The P-value is yet to be determined (Round to four decimal places as needed).**Calculator Display Summary:**- **1-PropZTest Summary:** - \( \text{prop} < 0.11 \) - \( z = -1.534791494 \) - \( p = 0.06241735264 \) (Preliminary P-value) - \( \hat{p} = 0.0808823529 \) (Sample proportion) - \( n = 272 \)This data allows students to analyze the hypothesis test structure, understand the implications of the test statistic value, and interpret the P-value for decision-making regarding the hypothesis.

a) The claim of the test is p<0.11.The sign in the claim is less than. Thus, the test is left-tailed test.b) From the output, the test statistic value is -1.53.c) From the output, the P-value is 0.0624.

Answered: A certain drug is used to treat asthma.…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A sample of size 5 was collected from an unknown population 15 15 16 16 17 1. Use the table of expected z-scores (rounded to the nearest tenth) below to construct the normality plot with expected z-scores on the x-axis and the observations on the y-axis: 6 -1.3 -0.6 -0.2 0.2 0.6 1.3 5 -1.2 -0.5 0 0.5 1.2 -1 19 18 normal O not normal Clear All Draw: 17- 16- 14 T 15- رها 1 2 7 -1.4 -0.8 -0.4 0 0.4 0.8 1.4 8 -1.4 -0.9 -0.5 -0.2 0.2 0.5 0.9 1.4 9 -1.5 -0.9 -0.6 -0.3 0 0.3 0.6 0.9 1.5 2. Based on whether the pattern above is linear or not, in your opinion, was the sample drawn from a normal population or not?
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If a standard deviation is 1.4 away from a mean of 7.2 what is the z score of an x value of 10
This assignment is worth 1 points. The extra point will be added to your overall course grade. For example: if you receive an 88% in the course you can receive up to 1 point giving you a new score of 89%. The following rubric will be used. 0.25 point for drawing the normal distribution curve with the mean value labeled on the curve and the appropriate area shaded. 0.25 point for determining the value of the standard deviation of the sample mean. 0.5 point for finding the correct probability. All work must be shown in order to receive any credit. Please upload your completed assignment here. The length of time taken on the SAT for a group of students is normally distributed with a mean of 2.5 hours and a standard deviation of 0.25 hours. A sample size of n = 60 is drawn randomly from the population. Find the probability that the sample mean is between two hours and three hours.
A sample of size 8 was collected from an unknown population 0 1126 10 11 20 1. Use the table of expected z-scores (rounded to the nearest tenth) below to construct the normality plot with expected z-scores on the x-axis and the observations on the y-axis: 5 -1.2 -0.5 0 0.5 1.2 Clear All Draw: 22- 2 not normal normal 19 # 6 -1.3 -0.6 -0.2 0.2 0.6 1.3 7 -1.4 -0.8 -0.4 0 0.4 0.8 1.4 8 -1.4 -0.9 -0.5 -0.2 0.2 0.5 0.9 1.4 9 -1.5 -0.9 -0.6 -0.3 0 0.3 0.6 0.9 1.5 2. Based on whether the pattern above is linear or not, in your opinion, was the sample drawn from a normal population or not?
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The average house has 13 paintings on its walls. Is the mean different for houses owned by teachers? The data show the results of a survey of 12 teachers who were asked how many paintings they have in their houses. Assume that the distribution of the population is normal. 12, 14, 14, 14, 15, 14, 14, 14, 12, 13, 15, 14 What can be concluded at the αα = 0.01 level of significance? For this study, we should use The null and alternative hypotheses would be: H0:H0: H1:H1: The test statistic = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is αα Based on this, we should the null hypothesis. Thus, the final conclusion is that ... The data suggest the population mean is not significantly different from 13 at αα = 0.01, so there is sufficient evidence to conclude that the population mean number of paintings that are in teachers' houses is equal to 13. The data…
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