A certain brand of automobile tire has a mean life span of 37,000 miles and a standard deviation of 2,400 miles. (Assume the life spans of the tires have a bell-shape distribution.) (a) Tne ire spans or inree ranaomıy seiectea tires are 33,000 miies, 38,000 miies, ana 32,000 miies. Fina tne z-score tnat corresponas to eacn iure span. For the life span of 33,000 miles, z-score is 1.67 (Round to the nearest hundredth as needed.) For the life span of 38,000 miles, z-score is 0.42 (Round to the nearest hundredth as needed.) For the life span of 32,000 miles, z-score is 2.08 (Round to the nearest hundredth as needed.) According to the z-scores, would the life spans of any of these tires be considered unusual? O Yes O No (b) The life spans of three randomly selected tires are 34,600 miles, 39,400 miles, and 37,000 miles. Using the empirical rule, find the percentile that corresponds to each life span. The life span 34,600 miles corresponds to the th percentile. The life span 39,400 miles corresponds to theth percentile. The life span 37,000 miles corresponds to theth percentile.

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A certain brand of automobile tire has a mean life span of 37,000 miles and a standard deviation of 2,400 (Assume the life spans of the tires have a​ bell-shaped distribution.)

​(a) The life spans of three randomly selected tires are 33,000 ​miles, 38,000 ​miles, and 32,000 miles. Find the​ z-score that corresponds to each life span.
For the life span of 33,000​miles, z-score is [1.67]
​(Round to the nearest hundredth as​ needed.)

For the life span of 38,000​miles, z-score is [0.42 ]
​(Round to the nearest hundredth as​ needed.)

For the life span of 32,000​miles, z-score is [2.08 ]
​(Round to the nearest hundredth as​ needed.)

Since we have the answer above, the question is;

According to the z-scores, would the life spans of any of these tires be considered unusual?

Yes or No.

 

A certain brand of automobile tire has a mean life span of 37,000 miles and a standard deviation of 2,400 miles. (Assume the life spans of the tires have a bell-shaper
distribution.)
(a) ine ire spans or tnree ranaomiy seiectea tires are 33,000 mIles, 38,U0u miies, and 32,000 miles. Fina the z-score tnat corresponas to eacn ie span.
For the life span of 33,000 miles, z-score is 1.67
(Round to the nearest hundredth as needed.)
For the life span of 38,000 miles, z-score is 0.42
(Round to the nearest hundredth as needed.)
For the life span of 32,000 miles, z-score is 2.08
(Round to the nearest hundredth as needed.)
According to the z-scores, would the life spans of any of these tires be considered unusual?
Yes
No
(b) The life spans of three randomly selected tires are 34,600 miles, 39,400 miles, and 37,000 miles. Using the empirical rule, find the percentile that corresponds to
each life span.
The life span 34,600 miles corresponds to the th percentile.
The life span 39,400 miles corresponds to the th percentile.
The life span 37,000 miles corresponds to the th percentile.
Transcribed Image Text:A certain brand of automobile tire has a mean life span of 37,000 miles and a standard deviation of 2,400 miles. (Assume the life spans of the tires have a bell-shaper distribution.) (a) ine ire spans or tnree ranaomiy seiectea tires are 33,000 mIles, 38,U0u miies, and 32,000 miles. Fina the z-score tnat corresponas to eacn ie span. For the life span of 33,000 miles, z-score is 1.67 (Round to the nearest hundredth as needed.) For the life span of 38,000 miles, z-score is 0.42 (Round to the nearest hundredth as needed.) For the life span of 32,000 miles, z-score is 2.08 (Round to the nearest hundredth as needed.) According to the z-scores, would the life spans of any of these tires be considered unusual? Yes No (b) The life spans of three randomly selected tires are 34,600 miles, 39,400 miles, and 37,000 miles. Using the empirical rule, find the percentile that corresponds to each life span. The life span 34,600 miles corresponds to the th percentile. The life span 39,400 miles corresponds to the th percentile. The life span 37,000 miles corresponds to the th percentile.
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