A cell phone manufacturer wishes to make a rectangular phone with fixedtotal surface area of 12, 000 mm2 that will have maximal screen area.The screen is surrounded by bezels on all sides with sizes of dh mm on theheight and dw mm on the the width. (So, for example, the width of thescreen would be the width of the phone minus 2 dw mm.)The following figure shows an illustration with adjustable values for dw anddh. The screen area varies as the the point P (w,h) is moved along theconstraint.JSXGraph y12 Copyright (C) see https://jsxgraph.org800height700600500dh = 32.00dw = 8.00400screen area = 5700P=(w,h)300200100O + +Suppose the bezels have sizes 4 mm on the width (dw) and 15 mm on theheight (dh). 20010050100150-100TC1.Suppose the bezels have sizes 4 mm on the width (duw) and 15 mm on the Uheight (dh).(a) What is the height of the phone?Tt(b) What is the width of the phone?(c) The dimensions for most phones have a height that is about twice thewidth. Is that the case for your answer?No the height to width ratio is closer to 1 to 1Yes, the height to width ratio is basically 2 to 1No, the height to width ratio is closer to 3 or more to 1•(d) Show your work used to compute w and h.8 +E

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A cell phone manufacturer wishes to make a rectangular phone with fixed total surface area of 12, 000 mm2 that will have maximal screen area. The screen is surrounded by bezels on all sides with sizes of dh mm on the height and dw mm on the the width. (So, for example, the width of the screen would be the width of the phone minus 2 dw mm.) The following figure shows an illustration with adjustable values for dw and dh. The screen area varies as the the point P (w,h) is moved along the constraint.

A cell phone manufacturer wishes to make a rectangular phone with fixed total surface area of 12, 000 mm2 that will have maximal screen area. The screen is surrounded by bezels on all sides with sizes of dh mm on the height and dw mm on the the width. (So, for example, the width of the screen would be the width of the phone minus 2 dw mm.) The following figure shows an illustration with adjustable values for dw and dh. The screen area varies as the the point P (w,h) is moved along the constraint.

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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A cell phone manufacturer wishes to make a rectangular phone with fixed
total surface area of 12, 000 mm2 that will have maximal screen area.
The screen is surrounded by bezels on all sides with sizes of dh mm on the
height and dw mm on the the width. (So, for example, the width of the
screen would be the width of the phone minus 2 dw mm.)
The following figure shows an illustration with adjustable values for dw and
dh. The screen area varies as the the point P (w,h) is moved along the
constraint.
JSXGraph y12 Copyright (C) see https://jsxgraph.org
800
height
700
600
500
dh = 32.00
dw = 8.00
400
screen area = 5700
P=(w,h)
300
200
100
O + +
Suppose the bezels have sizes 4 mm on the width (dw) and 15 mm on the
height (dh).

200
100
50
100
150
-100
TC
1.
Suppose the bezels have sizes 4 mm on the width (duw) and 15 mm on the U
height (dh).
(a) What is the height of the phone?
Tt
(b) What is the width of the phone?
(c) The dimensions for most phones have a height that is about twice the
width. Is that the case for your answer?
No the height to width ratio is closer to 1 to 1
Yes, the height to width ratio is basically 2 to 1
No, the height to width ratio is closer to 3 or more to 1•
(d) Show your work used to compute w and h.
8 +E

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