A cell exchanges materials with its environment to provide raw materials for cell processes and to remove waste products. The ratio of surface area to volume for a cell is a key factor in determining the efficiency of this exchange of materials. SAVR = surface area volume Part A a) Modelling the cell as a cube, find the surface area to volume ratio (SAVR) for cells of the following sizes: d = 2 x 10-6 m d = 5 x 10-6 m d = 10 x 10-6 m d ✓Part B Area of one face of the cube = d² Volume of cube = d³ b) Write a general formula for the SAVR of a cube of side d and use it to explain how SAVR changes with the size of the cube. (AC 3.1) c) Use the formula to find the value of d for which SAVR is equal to (i) 1000 m-¹, (ii) 1000000 m-1¹.
A cell exchanges materials with its environment to provide raw materials for cell processes and to remove waste products. The ratio of surface area to volume for a cell is a key factor in determining the efficiency of this exchange of materials. SAVR = surface area volume Part A a) Modelling the cell as a cube, find the surface area to volume ratio (SAVR) for cells of the following sizes: d = 2 x 10-6 m d = 5 x 10-6 m d = 10 x 10-6 m d ✓Part B Area of one face of the cube = d² Volume of cube = d³ b) Write a general formula for the SAVR of a cube of side d and use it to explain how SAVR changes with the size of the cube. (AC 3.1) c) Use the formula to find the value of d for which SAVR is equal to (i) 1000 m-¹, (ii) 1000000 m-1¹.
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.6: The Inverse Trigonometric Functions
Problem 94E
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Could you please help me with part B , I am really struggling
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