A cave rescue team lifts an injured spelunker directly upward and out of a sinkhole by means of a motor-driven cable. The lift is performed in three stages, each requiring a vertical distance of 10.0 m: (a) the initially stationary spelunker is accelerated to a speed of 5.00 m/s; (b) he is then lifted at the constant speed of 5.00 m/s; (c) finally he is decelerated to zero speed. How much work is done on the 80.0 kg rescuee by the force lifting him during each stage?

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A: Given: di=0.6m i^ + 0.79m j^ + 0.26m k^df=10.5m i^ + 15.0m j^ + 10.2m k^∆t = 15 sF = 4.0N i^ +7.0N…

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A:

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A: Given Data: Mass to rescue m=78 kg Vertical distance dv=9.70 m

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A:

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Q: A man pushing a crate of mass m = 92.0 kg at a speed of v = 0.860 m/s encounters a rough horizontal…

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Q: A cave rescue team lifts an injured spelunker directly upward and out of a sinkhole by means of a…

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A: See below

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Q: Chapter 5,#6. A man pushing a crate of mass  m = 92.0 kg  at a speed of  v = 0.870 m/s…

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A: