A catapult can project a projectile at a speed as high as 35.0 m/s.(a) If air resistance can be ignored, how high (in m) would a projectile launched at this speed rise if projected straight up?m(b) How long would the projectile be in the air (in s)?SNeed Help?Read It

Name: A catapult can project a projectile at a speed as high as 35.0 m/s.(a
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Description: A catapult can project a projectile at a speed as high as 35.0 m/s.(a) If air resistance can be ignored, how high (in m) would a projectile launched at this speed rise if projected straight up?m(b) How long would the projectile be in the air (in s)?

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College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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A catapult can project a projectile at a speed as high as 35.0 m/s.
(a) If air resistance can be ignored, how high (in m) would a projectile launched at this speed rise if projected straight up?
m
(b) How long would the projectile be in the air (in s)?
S
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Expert Solution

Step 1

Given the speed of the projectile $v = 35.0 m / s$

(a) height of the projectile h=?

we can calculate this by $v^{2} = u^{2} + 2 a s$

when the projectile is on the maximum height the speed of the projectile will be 0 at that moment and acceleration will be acceleration due to gravity and the direction will be negative

$0^{2} = 35 . 0^{2} + 2 (- 9.8) h h = 62.5 m$

so the projectile will go maximum height of 62.5m.

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