A catalyst works by providing an alternate reaction mechanism with a lower activation energy. A certain reaction has a rate 60 times faster when a catalyst is added. Calculate the difference of the activation energy after the catalyst is added: Eg(uncatalyzed) -Eg(catalyzed) = ? Assume a temperature of 298 K, and no change in frequency factor. 15. kJ/mol 10. kJ/mol 20. kJ/mol 25. kJ/mol O O O O
A catalyst works by providing an alternate reaction mechanism with a lower activation energy. A certain reaction has a rate 60 times faster when a catalyst is added. Calculate the difference of the activation energy after the catalyst is added: Eg(uncatalyzed) -Eg(catalyzed) = ? Assume a temperature of 298 K, and no change in frequency factor. 15. kJ/mol 10. kJ/mol 20. kJ/mol 25. kJ/mol O O O O
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![A catalyst works by providing an alternate reaction mechanism with a lower activation energy. A certain reaction has a rate 60 times faster when a catalyst is added. Calculate the difference of the activation energy after the catalyst is added:
\[ E_a (\text{uncatalyzed}) - E_a (\text{catalyzed}) = ? \]
Assume a temperature of 298 K, and no change in frequency factor.
- ○ 15 kJ/mol
- ○ 10 kJ/mol
- ○ 20 kJ/mol
- ○ 25 kJ/mol](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2a163f18-29bc-4cae-aa7e-1a32645d5b83%2Fca5ef499-7e6f-47f1-817d-db3b49cc497a%2Flo0df8x_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A catalyst works by providing an alternate reaction mechanism with a lower activation energy. A certain reaction has a rate 60 times faster when a catalyst is added. Calculate the difference of the activation energy after the catalyst is added:
\[ E_a (\text{uncatalyzed}) - E_a (\text{catalyzed}) = ? \]
Assume a temperature of 298 K, and no change in frequency factor.
- ○ 15 kJ/mol
- ○ 10 kJ/mol
- ○ 20 kJ/mol
- ○ 25 kJ/mol
Expert Solution
Step 1
To calculate the difference in activation energy for un-catalysed and catalysed reaction , we would would Arrhenius equation .
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