A catalyst decreases the activation energy of a particular exothermic reaction by 44 kJ/mol, to 69 kJ/mol. Assuming that the mechanism has only one step, and that the products are 68 kJ lower in energy than the reactants, sketch approximate energy level diagrams for the catalyzed and uncatalyzed reactions. What is the activation energy for the uncatalyzed reverse reaction? Answer: 181 What is the rate constant at 310 K? (Use Si units. For example, use seconds not minutes or hours.) Answer: What is the rate constant at 315K? Answer: What is the activation energy (in J/mol)? Answer: in a first-order decay:
A catalyst decreases the activation energy of a particular exothermic reaction by 44 kJ/mol, to 69 kJ/mol. Assuming that the mechanism has only one step, and that the products are 68 kJ lower in energy than the reactants, sketch approximate energy level diagrams for the catalyzed and uncatalyzed reactions. What is the activation energy for the uncatalyzed reverse reaction? Answer: 181 What is the rate constant at 310 K? (Use Si units. For example, use seconds not minutes or hours.) Answer: What is the rate constant at 315K? Answer: What is the activation energy (in J/mol)? Answer: in a first-order decay:
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:A catalyst decreases the activation energy of a particular exothermic reaction by 44 kJ/mol, to 69 kJ/mol. Assuming that the
mechanism has only one step, and that the products are 68 kJ lower in energy than the reactants, sketch approximate energy-
level diagrams for the catalyzed and uncatalyzed reactions.
What is the activation energy for the uncatalyzed reverse reaction?
Answer:
181
What is the rate constant at 310 K? (Use Si units. For example, use seconds not minutes or hours.)
Answer:
What is the rate constant at 315K?
Answer:
What is the activation energy (in J/mol)?
Answer:
ide in a first-order decay:
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