A cascade refrigeration system serves a 75 ton evaporator at 119.4 KPa. The system uses direct contact cascade condenser and the condenser pressure is 1157 KPa. The intermediate pressure is 432 KPa. Find the mass flowrate in kg/min in the low pressure loop.
A cascade refrigeration system serves a 75 ton evaporator at 119.4 KPa. The system uses direct contact cascade condenser and the condenser pressure is 1157 KPa. The intermediate pressure is 432 KPa. Find the mass flowrate in kg/min in the low pressure loop.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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![The following values for Ammonia were obtained:
At 119.4 KPa
ha = 1422.86 KJ/kg
Sa = 1.600 KJ/kg-K
At 1557 KPa
he = 390.59 KJ/kg
%3D
At 432 KPa
h = 1600 KJ/kg
h = 200.47 KJ/kg
ha = 1461.81 KJ/kg
Sa = 1.638 KJ/kg-K
%3D
%3D
A cascade refrigeration system serves a 75 ton evaporator at 119.4 KPa. The system
uses direct contact cascade condenser and the condenser pressure is 1157 KPa. The
intermediate pressure is 432 KPa.
Find the mass flowrate in kg/min in the low pressure loop.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb6fb74c1-775d-46fb-8fdc-7394c659bae3%2F7daec4fd-758e-41ae-bfea-d1bddf7fd0cc%2F2giza1_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The following values for Ammonia were obtained:
At 119.4 KPa
ha = 1422.86 KJ/kg
Sa = 1.600 KJ/kg-K
At 1557 KPa
he = 390.59 KJ/kg
%3D
At 432 KPa
h = 1600 KJ/kg
h = 200.47 KJ/kg
ha = 1461.81 KJ/kg
Sa = 1.638 KJ/kg-K
%3D
%3D
A cascade refrigeration system serves a 75 ton evaporator at 119.4 KPa. The system
uses direct contact cascade condenser and the condenser pressure is 1157 KPa. The
intermediate pressure is 432 KPa.
Find the mass flowrate in kg/min in the low pressure loop.
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