A cartesian equation of the parametric curve x = 12t + 11 E - 5, y = JE is OAx = (3y – 1 ( 4y +. = (4y -1)(3y +s) OB. 3y-1)(4y -. X = OD. X = [ - (3y + 1)(4y – s) (3y +1)(4y – 5) OE No solution

Q: x^4-x^2=6

A: To find: The value of x. Given: The equation is x4-x2=6 Calculation: Assume x2 as t, then equation…

Q: 2) Is A P Q R a right angle triangle P(-5,3) Q(-7,8) R(3, 12) and it. name

A:

Q: Complete the parametric equations of the point (-6,-5,-1) and perpendicular to the plane 4x-2y+3z=7…

A: Given query is to find parametric equation.

Q: a(t) Write the Cartesian equation of the line given by the parametric equations < y(t) 1- 9t -1+t.…

A:

Q: Match the parametric equations with the graphs labeled I-VI. Give reasons for your choices. I -1.0 2…

A:

Q: 1. Express the given parametric curve by an equation in x and (a) x = 8t²-5, y = 2t - 1, for t€…

A:

Q: Identify the parametric equations that represent the same path as the following parametric…

A: the given path is  x=t y=3t2-4 take t=x y=3x2-4.............the given path

Q: 7. Calculate dy/dx at the point indicated: f(0) = (7tan O, cos O), 0=/4

A: Here we will use the concept of parametric equation and Derivative of parametric ewyations

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A: given  y=(5-x)2

Q: Suppose parametric equations for the line segment between (4, 2) and (4, - 2) have the form: [ x(t)…

A: The line segment between the points (4, 2) and (4, -2) has parametric equations,It is also given…