A Cartesian and a polar graph of 3 1=2 - 5 cos (40) are given. Identify the points on the polar graph that correspond to the points shown on the Cartesian graph. T VoV B 12T o LOO 5 (O N 8 8 X

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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Problem 1RQ
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Question
A Cartesian and a
polar graph of
3
1=2
- 5 cos (40)
are given. Identify
the points on the
polar graph that
correspond to the
points shown on
the Cartesian
graph.
JAM
O
O
12π
ⒸON
-8
LO
to
8
Transcribed Image Text:A Cartesian and a polar graph of 3 1=2 - 5 cos (40) are given. Identify the points on the polar graph that correspond to the points shown on the Cartesian graph. JAM O O 12π ⒸON -8 LO to 8
Which point on the polar graph corresponds to point A on the Cartesian graph?
point
Which point on the polar graph corresponds to point B on the Cartesian graph?
point
Which point on the polar graph corresponds to point C on the Cartesian graph?
point
Transcribed Image Text:Which point on the polar graph corresponds to point A on the Cartesian graph? point Which point on the polar graph corresponds to point B on the Cartesian graph? point Which point on the polar graph corresponds to point C on the Cartesian graph? point
Expert Solution
Step 1: Description of given data

From the given polar curve of r equals 3 over 2 minus 5 cos left parenthesis 4 theta right parenthesis

Advanced Math homework question answer, step 1, image 1

Given that a polar graph is periodic with a period,theta equals pi over 2

The point A is obtained by substituting the maximum value of r as follows:

r equals 3 over 2 minus 5 cos left parenthesis 4 theta right parenthesis equals 3 over 2 minus 5 left parenthesis negative 1 right parenthesis equals 1.5 plus 5 equals 6.5

i.e., 

cos left parenthesis 4 theta right parenthesis equals negative 1
4 theta equals 3 pi
theta equals fraction numerator 3 pi over denominator 4 end fraction

therefore space theta subscript A equals fraction numerator 3 pi over denominator 4 end fractionr subscript A equals 6.5

Similarly for point B:

The point B is obtained by substituting the minimum value of r as follows:

r equals 3 over 2 minus 5 cos left parenthesis 4 theta right parenthesis equals 3 over 2 minus 5 left parenthesis 1 right parenthesis equals 1.5 minus 5 equals negative 3.5

i.e.,

cos left parenthesis 4 theta right parenthesis equals 1
4 theta equals 6 pi
theta equals fraction numerator 3 pi over denominator 2 end fraction 

therefore space theta subscript B equals fraction numerator 3 pi over denominator 2 end fraction comma space r subscript B equals negative 3.5

Now point C is obtained by substituting r equals 0

3 over 2 minus 5 cos left parenthesis 4 theta right parenthesis equals 0
5 cos left parenthesis 4 theta right parenthesis equals 3 over 2
cos left parenthesis 4 theta right parenthesis equals 3 over 10
theta equals 1 fourth cos to the power of negative 1 end exponent open parentheses 3 over 10 close parentheses

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