A certain genetic characteristic of a particular plant can appear in one of three forms (phenotypes). A researcher has developed a theory, according to which the hypothesized proportions areP₁ = 0.25, P₂ = 0.50, and P3 = 0.25. A random sample of 200 plants yields x² = 4.76.(a) Carry out a test of the null hypothesis that the theory is correct, using level of significance a = 0.05.Use technology to calculate the P-value. (Round your answer to four decimal places.)P-value =What can you conclude?O Reject Ho. We have convincing evidence that the theory is incorrect.O Fail to reject H. We have convincing evidence that the theory is incorrect.Fail to reject Ho. We do not have convincing evidence that the theory is incorrect.O Reject H. We do not have convincing evidence evidence that the theory is incorrect.(b) Suppose that a random sample of 300 plants had resulted in the same value of x². How would the analysis and conclusion differ from those in part (a)?O The previous analysis did not yield a significant result and the null hypothesis failed to be rejected. The new analysis would yield a significant result and the null hypothesis would berejected.O The analysis and conclusions would not change.O The previous analysis did not yield a significant result and the null hypothesis was rejected. The new analysis would yield a significant result and the null hypothesis would fail to berejected.O The previous analysis yielded a significant result and the null hypothesis failed to be rejected. The new analysis would not yield a significant result and the null hypothesis would berejected.O The previous analysis yielded a significant result and the null hypothesis was rejected. The new analysis would not yield a significant result and the null hypothesis would fail to berejected.

Let p1, p2, and p3 be the three population proportions.Given that,No. of plants Test statistic No.…

Answered: (a) Carry out a test of the null…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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State whether the standardized test statistic t indicates that you should reject the null hypothesis. Explain. (a) t =1.667 (b) t =0 (c) t= -1.552 (d) t= -1.705 (look at image below)
MORE BENEFITS OF EATING ORGANIC Using specific data, we find a significant difference in the proportion of fruit flies surviving after 13 days between those eating organic potatoes and those eating conventional (not organic) potatoes. This exercise asks you to conduct a hypothesis test using additional data. In this case, we are testing Họ : Po = Pc Ha: Po > Pc where p, and p. represent the proportion of fruit flies alive at the end of the given time frame of those eating organic food and those eating conventional food, respectively. Use a 5 % significance level. Effect of Organic Bananas After 25 Days After 25 days, the proportion of fruit flies eating organic bananas still alive is 0.45 , while the proportion still alive eating conventional bananas is 0.42. The standard error for the difference in proportions is 0.029. What is the value of the test statistic? Round your answer to two decimal places. z = i What is the p-value? Round your answer to three decimal places. p-value = What…
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Test the hypothesis using the P-value approach. Be sure to verify the requirements of the test. Ho: p=0.3 versus H₁: p>0.3 n=250; x = 95, a = 0.05 Is npo (1-Po) ≥ 10? O Yes O No Use technology to find the P-value. P-value= (Round to three decimal places as needed.) .. the null hypothesis, because the P-value is than a
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Test the hypothesis using the P-value approach. Be sure to verify the requirements of the test. Ho: p=0.8 versus H: p>0.8 n=200; x=175, a= 0.05 Is npo (1-Po) 210? Yes O No Use technology to find the P-value. P-value = (Round to three decimal places as needed.) the null hypothesis, because the P-value is than a. Time Re 20 F7 F8 F9 esc F2 F3 F4 F5 F1 %23 24
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