A care antenna is four meters long (starting at x = 0) and has a density of p(x) = Vr+e². %3D

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Author:James Stewart
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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Problem 21:**

A car antenna is four meters long (starting at \( x = 0 \)) and has a density function given by \(\rho(x) = \sqrt{x} + e^{-x}\). Find the mass of this antenna.

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**Explanation:**

To determine the mass of the antenna, we consider the function \(\rho(x)\) which gives the density at any point \(x\) along the length of the antenna. The mass can be calculated by integrating the density function over the interval from 0 to 4 meters (the length of the antenna).

The integral to find the mass \(M\) is:

\[ 
M = \int_{0}^{4} \left( \sqrt{x} + e^{-x} \right) \, dx 
\]

This integral will give the total mass of the antenna by summing up the contributions from each infinitesimally small segment along its length.
Transcribed Image Text:**Problem 21:** A car antenna is four meters long (starting at \( x = 0 \)) and has a density function given by \(\rho(x) = \sqrt{x} + e^{-x}\). Find the mass of this antenna. --- **Explanation:** To determine the mass of the antenna, we consider the function \(\rho(x)\) which gives the density at any point \(x\) along the length of the antenna. The mass can be calculated by integrating the density function over the interval from 0 to 4 meters (the length of the antenna). The integral to find the mass \(M\) is: \[ M = \int_{0}^{4} \left( \sqrt{x} + e^{-x} \right) \, dx \] This integral will give the total mass of the antenna by summing up the contributions from each infinitesimally small segment along its length.
Expert Solution
Step 1

Given data:

 

The expression for the density of the antenna is ρ(x)=x1/2+e-x.

The given length of the antenna is l=4 m.

 

The expression for the mass of the antenna is,

M=0lρ(x)dx

 

 

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