A cardioid is given by the equation x² + y² = (2x²+2y²-x)². Find the equation for the tangent line to the cardioid at the point (0,2). Hint: the algebra will be easier of you plug in your values (x, y) = (0, 1) before solving for (but after taking all derivatives). dy dx

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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A cardioid is given by the equation x² + y² = (2x²+2y²-x)². Find the equation
for the tangent line to the cardioid at the point (0,2).
Hint: the algebra will be easier of you plug in your values (x, y) = (0, 1)
before solving for (but after taking all derivatives).
dy
dx
Transcribed Image Text:A cardioid is given by the equation x² + y² = (2x²+2y²-x)². Find the equation for the tangent line to the cardioid at the point (0,2). Hint: the algebra will be easier of you plug in your values (x, y) = (0, 1) before solving for (but after taking all derivatives). dy dx
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Follow-up Question

Where did you get dy/dx(16x^2y + 16y^3 - 8xy) from?

2x+2y dy
dx
=
16x3+16xy2-bx2-4x24y2+2х
+ dy (16x³y+16y3-8 ху
Transcribed Image Text:2x+2y dy dx = 16x3+16xy2-bx2-4x24y2+2х + dy (16x³y+16y3-8 ху
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