A car wheel 30 cm in radius is turning at a rate of 8.0 rev/s when the car begins to slow uniformly to rest in a time of 14 s. Find the number of revolutions made by the wheel and the distance the car goes in the 14 s.
Angular speed, acceleration and displacement
Angular acceleration is defined as the rate of change in angular velocity with respect to time. It has both magnitude and direction. So, it is a vector quantity.
Angular Position
Before diving into angular position, one should understand the basics of position and its importance along with usage in day-to-day life. When one talks of position, it’s always relative with respect to some other object. For example, position of earth with respect to sun, position of school with respect to house, etc. Angular position is the rotational analogue of linear position.
(Question has already been answered)
Can you explain this solution?
Solution:
Distance = (56 x 2 x 3.14) x 0.30 = 105.56 m
I can't understand this part:
Angular displacement = (02 - 82)/(2x(-0.571)) = 56 revolutions
Trending now
This is a popular solution!
Step by step
Solved in 2 steps
