A car used 50 liters of gasoline and traveled a total distance of 350 km. The car's fuel efficiency is 4 km per liter on the highway and 2.5 km per liter in the city. The variable z will represent the number of liters used on the highway. Which equation could be used to find z? OA. 4z +2.5(50 - h) = 350 OB. 2.5(50-z) + 4z = 350 OC. 2.5(50 + h) + 4z = 350 O D. 4z + 2.5(50 + z) = 350

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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What is the difference between 3 hrs 49
min and 9 hrs 17 min?
OA. 5hrs 28min
B. 6hrs 32min
C. 4hrs 58min
OD. 5hrs 42min
Transcribed Image Text:What is the difference between 3 hrs 49 min and 9 hrs 17 min? OA. 5hrs 28min B. 6hrs 32min C. 4hrs 58min OD. 5hrs 42min
A car used 50 liters of gasoline and
traveled a total distance of 350 km. The
car's fuel efficiency is 4 km per liter on the
highway and 2.5 km per liter in the city.
The variable z will represent the number of
liters used on the highway. Which equation
could be used to find z?
OA. 4z +2.5(50 - h) = 350
OB. 2.5(50-z) + 4z = 350
O c. 2.5(50+ h) + 4z = 350
C.
OD. 4z +2.5(50 + z) = 350
Transcribed Image Text:A car used 50 liters of gasoline and traveled a total distance of 350 km. The car's fuel efficiency is 4 km per liter on the highway and 2.5 km per liter in the city. The variable z will represent the number of liters used on the highway. Which equation could be used to find z? OA. 4z +2.5(50 - h) = 350 OB. 2.5(50-z) + 4z = 350 O c. 2.5(50+ h) + 4z = 350 C. OD. 4z +2.5(50 + z) = 350
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