A car travels along a straight road for 30 seconds starting at time t = 0. Its acceleration in ft/sec² is given by the linear graph below for the time interval [0, 30]. At t = 0, the velocity of the car is 0 and its position is 10. What is the total distance the car travels in this 30 second interval? Your must show your work but you may use your calculator to evaluate. Give 3 decimal places in your answer and include units. +4

Calculus: Early Transcendentals
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ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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2. A car travels along a straight road for 30 seconds starting at time t = 0. Its
acceleration in ft/sec² is given by the linear graph below for the time interval [0, 30].
At t = 0, the velocity of the car is 0 and its position is 10.
What is the total distance the car travels in this 30 second interval? Your must show
your work but you may use your calculator to evaluate. Give 3 decimal places in your
answer and include units.
0
-5
-10
-15
0
12
00
10
12
14
16
18
20
22
24
26
28
30
Transcribed Image Text:2. A car travels along a straight road for 30 seconds starting at time t = 0. Its acceleration in ft/sec² is given by the linear graph below for the time interval [0, 30]. At t = 0, the velocity of the car is 0 and its position is 10. What is the total distance the car travels in this 30 second interval? Your must show your work but you may use your calculator to evaluate. Give 3 decimal places in your answer and include units. 0 -5 -10 -15 0 12 00 10 12 14 16 18 20 22 24 26 28 30
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I don't understand why the sign was changed from + to - in the second line of step 6.

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Follow-up Question

I don't understand step 4, why it was necessary to find when velocity is 0 and why velocity is 0 at t=20. Thank you

https://www.bartleby.com/questions-and-answers/a-car-travels-along-a-straight-road-for-30-seconds-starting-at-time-t-0.-its-acceleration-in-ftsec-i/503f715e-e4c9-4cea-a5ab-93145db0dedd

Step 4
now find the time when v=0
V = 0
10t
-
10
+ (10 - 1) =
t²
2
-
here t=0 is the starting point so we can divide both sides by t
10-\frac{t}{2}=0
0
t
t=20
= 0
Transcribed Image Text:Step 4 now find the time when v=0 V = 0 10t - 10 + (10 - 1) = t² 2 - here t=0 is the starting point so we can divide both sides by t 10-\frac{t}{2}=0 0 t t=20 = 0
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