A car travels 25km due east and 30km in a direction 10° north of east. X component of the resultant displacement (in km) = Y component of the resultant displacement (in km) = %3D Magnitude of the resultant displacement (in km) The direction of the resultant displacement (North of East) =
A car travels 25km due east and 30km in a direction 10° north of east. X component of the resultant displacement (in km) = Y component of the resultant displacement (in km) = %3D Magnitude of the resultant displacement (in km) The direction of the resultant displacement (North of East) =
Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter1: Introduction And Vectors
Section: Chapter Questions
Problem 44P: Three displacement vectors of a croquet ball are shown in Figure P1.44, where |A|=20.0units,...
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![A car travels 25km due east and 30km in a direction 10° north of east.
X component of the resultant displacement (in km) =
Y component of the resultant displacement (in km) =
Magnitude of the resultant displacement (in km) =
The direction of the resultant displacement (North of East) =](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb4e399dc-7059-455a-a28f-44054a95a60f%2Fa0d93c92-feed-4065-96be-1a7000b4a0af%2Flpqeyfv_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A car travels 25km due east and 30km in a direction 10° north of east.
X component of the resultant displacement (in km) =
Y component of the resultant displacement (in km) =
Magnitude of the resultant displacement (in km) =
The direction of the resultant displacement (North of East) =
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