Help The image displays a multiple-choice question format often found on educational websites. - On the left side, the number "12" is prominently displayed in a large, bold font, which likely indicates the question number in a series.- On the right side, there are five options, each associated with a small circle indicating a selection mechanism (often used in online quizzes for selecting answers): 1. 21 m. 2. 17 m. 3. 10 m. 4. 13 m. 5. 9 m.There are no graphs or diagrams present in the image. The options appear to be formatted for easy clicking, suggesting they are part of an interactive quiz or test. **Problem 12:**A car traveling at 4.0 m/s has a constant acceleration of 2.0 m/s² in the same direction as the velocity. After 3.0 seconds, the distance traveled is:### Solution:To find the distance traveled, you can use the kinematic equation:\[ s = ut + \frac{1}{2}at^2 \]Where:- \( s \) is the distance traveled,- \( u \) is the initial velocity (\( 4.0 \, \text{m/s} \)),- \( a \) is the acceleration (\( 2.0 \, \text{m/s}^2 \)),- \( t \) is the time (\( 3.0 \, \text{s} \)).Plugging in the values:\[ s = (4.0 \, \text{m/s})(3.0 \, \text{s}) + \frac{1}{2}(2.0 \, \text{m/s}^2)(3.0 \, \text{s})^2 \]\[ s = 12.0 \, \text{m} + \frac{1}{2}(2.0)(9.0) \]\[ s = 12.0 \, \text{m} + 9.0 \, \text{m} \]\[ s = 21.0 \, \text{m} \]Therefore, the car travels a distance of 21.0 meters in 3.0 seconds.

Name: Help The image displays a multiple-choice question format often found
Uploaded: 2024-03-05T11:56:34.000Z
Channel: Bartleby
Description: Help The image displays a multiple-choice question format often found on educational websites. - On the left side, the number "12" is prominently displayed in a large, bold font, which likely indicates the question number in a series.- On the right s