A car that weighs 550 kg locks its tires and ski
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A car that weighs 550 kg locks its tires and skids to a stop from and initial velocity of 14 m/s forward, covering a distance of 9.2 m
Draw a FBD of the car during the slide
Calculate the coefficient of kinetic friction between the tires and the surface of the road.
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- Ramp A block is given an initial velocity of 5.00 m/s up a frictionlessincline with an angle of 20.0° from horizontal. How far up the inclinedoes the block slide before turning around?A 5 kg box is at placed on a rough horizontal surface. The coefficient of kinetic friction between the surface and the box is 0.2. Now 20 N force is applied on the box 300 above horizontal. Label all forces acting on the box. Determine the acceleration of the box. If applied force is removed after 10 seconds, calculate total distance the box moves along the surface.A hockey puck on a frozen pond is given an initial speed of 20.0 m/s. If the puck always remains on the ice and slides 115 m before coming to rest, determine the coefficient of ki- netic friction between the puck and ice
- Forces: David is driving at 27.8 m/s during a storm when he suddenly notices cars 66.3 m ahead fully stopped due to lane closures. What is the minimum coefficient of kinetic friction needed to avoid an accident if David brakes immediately?Steps Step 1) Look up the value for the coefficient of kinetic friction between the steel ball and steel track. Step 2) The ball is raised up to a height near the top of the right side of the track. Record this as h2. Step 3) The ball is released with no initial velocity and allowed to roll down the track. Step 4) Determine the velocity of the ball when it reaches the bottom of the track. Step 5) Compare the calculated velocity of the ball at the bottom of the track with the value measured by the motion sensor. Step 6) The height the ball reaches on the opposite side of the track is recorded as h3. Step 7) Complete Tables 1 and 2. Table 1 mBall (kg) 0.05 0 (degrees) h2 (m) h3 (m) 30 0.85 0.75 Table 2 PE, (J) PE2 (J) PE3 (J) Vr1 (m/s) Vn2(m/s) | Vn3 (m/s) N (N) d (m) Wnc (J) Vh1 (meter) = 3.5 m/s Loss of Energy = .a) "A swimmer pushing off from the side of a pool. She pushes against the pool wall with her feet and accelerates in the direction opposite to her push" What is the concept of above situation and explain.