A car starts from rest and accelerates uniformly for tseconds to a speed v m/s. It maintains this speed for10 seconds and then comes to rest with a uniformretardation of 2 m/s2.Given that the total time of motion is 22 secondsand that the total distance moved is 160m find thevalue of t and of v.

Answered: Image /qna-images/answer/3c2fe7ac-7ac8-4dc6-9103-f616c1709ba3.jpg

Answered: A car starts from rest and accelerates…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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A Lamborghini Aventador SVJ, traveling at a constant speed of 280 ms-1 passes a police car at rest on the High 95, highway in south Florida. The policeman starts to move at the moment the speeder passes his car and accelerates at a constant rate of 15.0 ms-2 until he pulls even with the speeding Lamborghini. Find: (i) The time and the final velocity required for the police car to catch the speeding car. (ii) The distance travelled during the chase.
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The position of a body moving on a coordinate line is given by s = seconds. (a) Find the body's displacement and average velocity for the given time interval. Displacement = -30 Average velocity = -6 Velocity at t = 6 is (b) Find the body's velocity at the endpoints of the interval. Velocity at t = 1 is -66 m/s 1 6 Acceleration at t = 6 is m 1 9 m/s (c) Find the body's acceleration at the endpoints of the interval. Acceleration at t = 1 is 204 m/s² S m/s 36 t² t m/s² for 1 ≤ t ≤ 6, with s in meters and t in (d) When, if ever, during the interval does the body change direction? If there is more than one answer, enter a comma separated list. If the body never changes direction during the interval, enter NONE. t =
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The elevator in the new Engineering building moves from the ground to the top floor which is 28 meters. If the elevator can accelerate at 2.42 m/s2, decelerate at 1.21 m/s2, and reach a certain maximum speed. Calculate the height that the elevator must travel from rest (on the ground floor) before it decelerates to end up at rest on the top floor?
In the presence of friction, the descending velocity v of the particle is determined as follows. mxdv/dt = mg-yv ap m =mg -yv dt (a) Predict v through dimensional analysis. (b) Solve the differential equation directly and compare it with the dimensional analysis. please. help...

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