A car of mass, m = 1500 kg going at an initial speed, Vị = 30 m/s exits a main road onto a banked lane. The car slows down due to a gain in height and due to friction from its breaks. The final speed of the car, vf = 15 m/s after the car has travelled a distance, s = 100 m along the road and has been raised by a height, h = 10 m. %3D W=15 m/s V = 30 m/s h= 10 m What is the net force applied by the breaks of the car assuming that this force is constant in time?

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Chapter1: Units, Trigonometry. And Vectors
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A car of mass= 1500 kg going at an initial speed vi
A car of mass, m = 1500 kg going at an initial speed, V¡ = 30 m/s exits a main road
onto a banked lane. The car slows down due to a gain in height and due to friction
from its breaks. The final speed of the car, Vf = 15 m/s after the car has travelled a
distance, s = 100 m along the road and has been raised by a height, h = 10 m.
W=15 m/s
V = 30 m/s
h= 10 m
What is the net force applied by the breaks of the car assuming that this force is
constant in time?
Transcribed Image Text:A car of mass, m = 1500 kg going at an initial speed, V¡ = 30 m/s exits a main road onto a banked lane. The car slows down due to a gain in height and due to friction from its breaks. The final speed of the car, Vf = 15 m/s after the car has travelled a distance, s = 100 m along the road and has been raised by a height, h = 10 m. W=15 m/s V = 30 m/s h= 10 m What is the net force applied by the breaks of the car assuming that this force is constant in time?
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