A capacitor of 3.23μF has an area of 6.35mm 2. Determine the separation distance between the two plates. If the new capacitance is now 5.63mF, what is the value of the dielectric inserted to the capacitor? What is the new voltage if the capacitor is connected to a 110 volts source? If the electric field created by two plates 8.99x10^4 N/C and a working voltage of 63 volts. Will the capacitor experience a dielectric breakdown? Please disregard everything except the final question. The solutions I've done are correct to the best of my knowledge, except for the last one. My instructor has marked my answer to the question about dielectric breakdown as wrong (it having a dielectric breakdown) , however, I do not understand why. I've asked my instructor if whether the working voltage is the voltage that dielectric breakdown would occur, or if it's the voltage the circuit is running on. My instructor said that "That will be in the new voltage of the capacitor" Please explain how the dialectric breakdown would occur and whether or not it would happen in this scenario.
Dielectric Constant Of Water
Water constitutes about 70% of earth. Some important distinguishing properties of water are high molar concentration, small dissociation constant and high dielectric constant.
Electrostatic Potential and Capacitance
An electrostatic force is a force caused by stationary electric charges /fields. The electrostatic force is caused by the transfer of electrons in conducting materials. Coulomb’s law determines the amount of force between two stationary, charged particles. The electric force is the force which acts between two stationary charges. It is also called Coulomb force.
A capacitor of 3.23μF has an area of 6.35mm 2. Determine the separation distance between the two plates. If the new capacitance is now 5.63mF, what is the value of the dielectric inserted to the capacitor? What is the new voltage if the capacitor is connected to a 110 volts source? If the electric field created by two plates 8.99x10^4 N/C and a working voltage of 63 volts. Will the capacitor experience a dielectric breakdown?
Please disregard everything except the final question. The solutions I've done are correct to the best of my knowledge, except for the last one. My instructor has marked my answer to the question about dielectric breakdown as wrong (it having a dielectric breakdown) , however, I do not understand why.
I've asked my instructor if whether the working voltage is the voltage that dielectric breakdown would occur, or if it's the voltage the circuit is running on. My instructor said that "That will be in the new voltage of the capacitor"
Please explain how the dialectric breakdown would occur and whether or not it would happen in this scenario.
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