A capacitor is connected to a 20 V battery through a resistance of 1002. It is found that the potential difference across the capacitor rises to 2 V in 1 µs. The capacitance of the capacitor is ...µF.
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- Don't copy please, just need answer, no explanation.A 13.0 kΩ resistor and a capacitor are connected in series and then a 20.0 V potential difference is suddenly applied across them. The potential difference across the capacitor rises to 5.0 V in 4.8 μs. Find the capacitance of the capacitor. (Your result must be in multiples of 10-10 Farads and include 2 digit after the decimal point. That means if, for example, you get a result of a 9.22x10-10 just type 9.22 in the answer box. Maximum of 5% of error is accepted in your answer. )Part A: A resistor has a current of 50 mA and an electrical resistance of 5 k ohms. What is the voltage drop across the resistor? Part B: A capacitor with a capacitance of 14 F has a charge of 15 C stored on it. What is the voltage change across the capacitor?
- A capacitor with capacitance C = 5 µF is charged to a voltage V = 10V. It is then discharged through a resistor R=2 MQ. At what time after the start of the discharge process has the voltage across the capacitor fallen to 1V?A) what is the equivalent capacitance of C eq of the circuit? B) Find the voltage across and charge stored on EACH of the capacitors in the circuit.A 10.0 μF capacitor is charged to 50.0 V and is then connected across a 460 Ω resistor only. What is the voltage across the resistor after 7.60 ms?