A cantilevered prismatic beam (ABC) has a concentrated load applied at the mid span (B). The beam has a square cross-section of side length, a. The left hand side (A) is a fixed support. A cable of length 950.0 is used to support the right hand side of the beam (C). The support at the top of the cable (D) can be considered a pinned support. You are tasked with calculating the magnitude of the reaction force at Point D. Both the cable and the beam are fabricated from the same material and have an elastic modulus, E, of 200.0 GPa. The deflection of the cable is non-zero and needs to be accounted for when calculating the reaction force. Beam cross-section ka A L/2 B The applied forced P, is 5,250.0 N; The length of the beam L, is 1,400.0 mm; The side length of the beam, a, is 55.0 mm The length of the cable, Lc, is 950.0 mm. The diameter of the cable, d, is 5.0 mm. The elastic modulus, E, is 200.0 GPa. L/2 D C Lc

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Laws of Equilibrium

A body is said to be in equilibrium if the system of forces acting on the body tends to keep the body at rest, in other words, there is no translation motion or net torque on the body. Under such conditions, the equilibrium conditions are to be applied to analyze the condition. The branch of mechanics that deals with this condition is known as 'statics'. Under equilibrium, there are no net forces on the body.