A cannon ball is launched into the air with an upward velocity of 336 feet per second, from a 14-foot tall cannon. The height hh of the cannon ball after tt seconds can be found using the equation h=−16t2+336t+14h=-16t2+336t+14. A)  What was the initial height of the cannon ball?         feet B) How many seconds will it take for the cannon ball to hit the ground?     seconds   {Round to 3 decimal place.

Glencoe Physics: Principles and Problems, Student Edition
1st Edition
ISBN:9780078807213
Author:Paul W. Zitzewitz
Publisher:Paul W. Zitzewitz
Chapter6: Motion In Two Dimensions
Section6.3: Relative Velocity
Problem 27PP
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A cannon ball is launched into the air with an upward velocity of 336 feet per second, from a 14-foot tall cannon. The height hh of the cannon ball after tt seconds can be found using the equation h=−16t2+336t+14h=-16t2+336t+14.

A)  What was the initial height of the cannon ball?         feet

B) How many seconds will it take for the cannon ball to hit the ground?     seconds   {Round to 3 decimal place.}

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