(a) Calculate the tension in a vertical strand of spiderweb if a spider of mass 7.00 x 10 kg hangs motionless on it. N (b) Calculate the tension in a horizontal strand of spiderweb if the same spider sits motionless in the middle of it much like the tightrope walker in Figure 4.13. The strand sags at an angle of 11.0° below the horizontal. N Compare this with the tension in the vertical strand (find their ratio). (tension in horizontal strand / tension in vertical strand) Ta Tu .... P net F=0 TR (b) TR Tu net F,-0 net F,=0 .....

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
icon
Related questions
Question

See attached

Certainly! Here's a transcription suitable for an educational website:

---

### Spiderweb Tension Calculations

#### Problem Description:

(a) **Calculate the tension in a vertical strand of spiderweb** if a spider of mass \(7.00 \times 10^{-5}\) kg hangs motionless on it.

\[ \text{Tension in vertical strand:} \, \underline{\qquad} \, \text{N} \]

(b) **Calculate the tension in a horizontal strand of spiderweb** if the same spider sits motionless in the middle of it, much like the tightrope walker depicted in Figure 4.13. The strand sags at an angle of \(11.0^\circ\) below the horizontal.

\[ \text{Tension in horizontal strand:} \, \underline{\qquad} \, \text{N} \]

**Compare this with the tension in the vertical strand (find their ratio).**

\[ \text{Ratio (tension in horizontal strand / tension in vertical strand):} \, \underline{\qquad} \]

#### Diagrams Explanation:

- **Figure (a):** This portrays a tightrope walker standing on a horizontal strand, with two symmetrical tensions (\(T_L\) and \(T_R\)) making an angle of \(5^\circ\) with the horizontal. The weight (\(W\)) is acting downwards.

- **Figure (b):** This diagram is broken into components:

  - **Left-side diagram:** Shows the vectors \(W\) and tensions \(T_R\) and \(T_L\), with the net force (\(\text{net } F = 0\)) indicating equilibrium.

  - **Middle diagram (vertical components):** Displays the vertical components of tensions (\(T_{L_y}\) and \(T_{R_y}\)) counteracting the weight (\(W\)), ensuring that \(\text{net } F_y = 0\).

  - **Right-side diagram (horizontal components):** Shows horizontal components of tensions balancing each other (\(T_{L_x}\) and \(T_{R_x}\)), maintaining \(\text{net } F_x = 0\).

---

This detailed breakdown helps students understand the physics of tension in spiderweb strands through vector analysis and equilibrium conditions.
Transcribed Image Text:Certainly! Here's a transcription suitable for an educational website: --- ### Spiderweb Tension Calculations #### Problem Description: (a) **Calculate the tension in a vertical strand of spiderweb** if a spider of mass \(7.00 \times 10^{-5}\) kg hangs motionless on it. \[ \text{Tension in vertical strand:} \, \underline{\qquad} \, \text{N} \] (b) **Calculate the tension in a horizontal strand of spiderweb** if the same spider sits motionless in the middle of it, much like the tightrope walker depicted in Figure 4.13. The strand sags at an angle of \(11.0^\circ\) below the horizontal. \[ \text{Tension in horizontal strand:} \, \underline{\qquad} \, \text{N} \] **Compare this with the tension in the vertical strand (find their ratio).** \[ \text{Ratio (tension in horizontal strand / tension in vertical strand):} \, \underline{\qquad} \] #### Diagrams Explanation: - **Figure (a):** This portrays a tightrope walker standing on a horizontal strand, with two symmetrical tensions (\(T_L\) and \(T_R\)) making an angle of \(5^\circ\) with the horizontal. The weight (\(W\)) is acting downwards. - **Figure (b):** This diagram is broken into components: - **Left-side diagram:** Shows the vectors \(W\) and tensions \(T_R\) and \(T_L\), with the net force (\(\text{net } F = 0\)) indicating equilibrium. - **Middle diagram (vertical components):** Displays the vertical components of tensions (\(T_{L_y}\) and \(T_{R_y}\)) counteracting the weight (\(W\)), ensuring that \(\text{net } F_y = 0\). - **Right-side diagram (horizontal components):** Shows horizontal components of tensions balancing each other (\(T_{L_x}\) and \(T_{R_x}\)), maintaining \(\text{net } F_x = 0\). --- This detailed breakdown helps students understand the physics of tension in spiderweb strands through vector analysis and equilibrium conditions.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 2 images

Blurred answer
Knowledge Booster
Sectioning basics
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Structural Analysis
Structural Analysis
Civil Engineering
ISBN:
9781337630931
Author:
KASSIMALI, Aslam.
Publisher:
Cengage,
Structural Analysis (10th Edition)
Structural Analysis (10th Edition)
Civil Engineering
ISBN:
9780134610672
Author:
Russell C. Hibbeler
Publisher:
PEARSON
Principles of Foundation Engineering (MindTap Cou…
Principles of Foundation Engineering (MindTap Cou…
Civil Engineering
ISBN:
9781337705028
Author:
Braja M. Das, Nagaratnam Sivakugan
Publisher:
Cengage Learning
Fundamentals of Structural Analysis
Fundamentals of Structural Analysis
Civil Engineering
ISBN:
9780073398006
Author:
Kenneth M. Leet Emeritus, Chia-Ming Uang, Joel Lanning
Publisher:
McGraw-Hill Education
Sustainable Energy
Sustainable Energy
Civil Engineering
ISBN:
9781337551663
Author:
DUNLAP, Richard A.
Publisher:
Cengage,
Traffic and Highway Engineering
Traffic and Highway Engineering
Civil Engineering
ISBN:
9781305156241
Author:
Garber, Nicholas J.
Publisher:
Cengage Learning