(a) Calculate the tension in a vertical strand of spiderweb if a spider of mass 7.00 x 10 kg hangs motionless on it. N (b) Calculate the tension in a horizontal strand of spiderweb if the same spider sits motionless in the middle of it much like the tightrope walker in Figure 4.13. The strand sags at an angle of 11.0° below the horizontal. N Compare this with the tension in the vertical strand (find their ratio). (tension in horizontal strand / tension in vertical strand) Ta Tu .... P net F=0 TR (b) TR Tu net F,-0 net F,=0 .....
(a) Calculate the tension in a vertical strand of spiderweb if a spider of mass 7.00 x 10 kg hangs motionless on it. N (b) Calculate the tension in a horizontal strand of spiderweb if the same spider sits motionless in the middle of it much like the tightrope walker in Figure 4.13. The strand sags at an angle of 11.0° below the horizontal. N Compare this with the tension in the vertical strand (find their ratio). (tension in horizontal strand / tension in vertical strand) Ta Tu .... P net F=0 TR (b) TR Tu net F,-0 net F,=0 .....
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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![Certainly! Here's a transcription suitable for an educational website:
---
### Spiderweb Tension Calculations
#### Problem Description:
(a) **Calculate the tension in a vertical strand of spiderweb** if a spider of mass \(7.00 \times 10^{-5}\) kg hangs motionless on it.
\[ \text{Tension in vertical strand:} \, \underline{\qquad} \, \text{N} \]
(b) **Calculate the tension in a horizontal strand of spiderweb** if the same spider sits motionless in the middle of it, much like the tightrope walker depicted in Figure 4.13. The strand sags at an angle of \(11.0^\circ\) below the horizontal.
\[ \text{Tension in horizontal strand:} \, \underline{\qquad} \, \text{N} \]
**Compare this with the tension in the vertical strand (find their ratio).**
\[ \text{Ratio (tension in horizontal strand / tension in vertical strand):} \, \underline{\qquad} \]
#### Diagrams Explanation:
- **Figure (a):** This portrays a tightrope walker standing on a horizontal strand, with two symmetrical tensions (\(T_L\) and \(T_R\)) making an angle of \(5^\circ\) with the horizontal. The weight (\(W\)) is acting downwards.
- **Figure (b):** This diagram is broken into components:
- **Left-side diagram:** Shows the vectors \(W\) and tensions \(T_R\) and \(T_L\), with the net force (\(\text{net } F = 0\)) indicating equilibrium.
- **Middle diagram (vertical components):** Displays the vertical components of tensions (\(T_{L_y}\) and \(T_{R_y}\)) counteracting the weight (\(W\)), ensuring that \(\text{net } F_y = 0\).
- **Right-side diagram (horizontal components):** Shows horizontal components of tensions balancing each other (\(T_{L_x}\) and \(T_{R_x}\)), maintaining \(\text{net } F_x = 0\).
---
This detailed breakdown helps students understand the physics of tension in spiderweb strands through vector analysis and equilibrium conditions.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb1ac0663-d6d8-4ebd-be91-be7471df5d85%2F9c515ae7-82d4-492c-ae72-8fad81907006%2F78jvqks_processed.png&w=3840&q=75)
Transcribed Image Text:Certainly! Here's a transcription suitable for an educational website:
---
### Spiderweb Tension Calculations
#### Problem Description:
(a) **Calculate the tension in a vertical strand of spiderweb** if a spider of mass \(7.00 \times 10^{-5}\) kg hangs motionless on it.
\[ \text{Tension in vertical strand:} \, \underline{\qquad} \, \text{N} \]
(b) **Calculate the tension in a horizontal strand of spiderweb** if the same spider sits motionless in the middle of it, much like the tightrope walker depicted in Figure 4.13. The strand sags at an angle of \(11.0^\circ\) below the horizontal.
\[ \text{Tension in horizontal strand:} \, \underline{\qquad} \, \text{N} \]
**Compare this with the tension in the vertical strand (find their ratio).**
\[ \text{Ratio (tension in horizontal strand / tension in vertical strand):} \, \underline{\qquad} \]
#### Diagrams Explanation:
- **Figure (a):** This portrays a tightrope walker standing on a horizontal strand, with two symmetrical tensions (\(T_L\) and \(T_R\)) making an angle of \(5^\circ\) with the horizontal. The weight (\(W\)) is acting downwards.
- **Figure (b):** This diagram is broken into components:
- **Left-side diagram:** Shows the vectors \(W\) and tensions \(T_R\) and \(T_L\), with the net force (\(\text{net } F = 0\)) indicating equilibrium.
- **Middle diagram (vertical components):** Displays the vertical components of tensions (\(T_{L_y}\) and \(T_{R_y}\)) counteracting the weight (\(W\)), ensuring that \(\text{net } F_y = 0\).
- **Right-side diagram (horizontal components):** Shows horizontal components of tensions balancing each other (\(T_{L_x}\) and \(T_{R_x}\)), maintaining \(\text{net } F_x = 0\).
---
This detailed breakdown helps students understand the physics of tension in spiderweb strands through vector analysis and equilibrium conditions.
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