a) Calculate the mean free path in meters of a nitrogen molecule (with a mass m=4.68×10-26 kg) located in Earth's atmosphere at sea level. Assume a temperature of T=300 K and a number density of particles of 1019 cm -3

icon
Related questions
Question

density of particles = 10^19 cm^-3

a) Calculate the mean free path in meters of a nitrogen molecule (with a mass \( m = 4.68 \times 10^{-26} \, \text{kg} \)) located in Earth's atmosphere at sea level. Assume a temperature of \( T = 300 \, \text{K} \) and a number density of particles of \( 10^{19} \, \text{cm}^{-3} \).

b) Assuming that the collision cross-section of the molecule is \( \sigma = 2 \times 10^{-10} \, \text{m} \), compute the collision frequency \( \nu \) in Hertz and the time between collisions \( t \) in seconds.
Transcribed Image Text:a) Calculate the mean free path in meters of a nitrogen molecule (with a mass \( m = 4.68 \times 10^{-26} \, \text{kg} \)) located in Earth's atmosphere at sea level. Assume a temperature of \( T = 300 \, \text{K} \) and a number density of particles of \( 10^{19} \, \text{cm}^{-3} \). b) Assuming that the collision cross-section of the molecule is \( \sigma = 2 \times 10^{-10} \, \text{m} \), compute the collision frequency \( \nu \) in Hertz and the time between collisions \( t \) in seconds.
Expert Solution
steps

Step by step

Solved in 2 steps with 1 images

Blurred answer
Similar questions