a) Calculate the absolute pressure at the bottom of a fresh-water lake at a depth of 32.6 m. Assume the density of the water is 1.00 x 10³ kg/m³ and the a 421106 Pa b) What force is exerted by the water on the window of an underwater vehicle at this depth if the window is circular and has a diameter of 33.0 cm? 143995.51 x 'our response differs from the correct answer by more than 100%. N Need Heln? Read It

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### Example Problem: Pressure and Force at Depth

**Problem Statement:**

(a) Calculate the absolute pressure at the bottom of a freshwater lake at a depth of 32.6 meters. Assume the density of water is 1.00 × 10³ kg/m³ and the air above is at a pressure of 101.3 kPa.

**Answer:**
\[ 421106\ \text{Pa} \]

**Detailed Explanation and Solution:**

The absolute pressure at a certain depth underwater can be calculated using the formula:
\[ P = P_0 + \rho g h \]
where:
- \( P \) is the absolute pressure at depth,
- \( P_0 \) is the atmospheric pressure at the surface (101.3 kPa or 101300 Pa),
- \( \rho \) is the density of the water (1.00 × 10³ kg/m³),
- \( g \) is the acceleration due to gravity (9.81 m/s²),
- \( h \) is the depth of the water (32.6 m).

Using the given values in the formula:
\[ P = 101300\ \text{Pa} + (1.00 \times 10^3\ \text{kg/m}^3 \times 9.81\ \text{m/s}^2 \times 32.6\ \text{m}) \]
\[ P = 101300\ \text{Pa} + 319806\ \text{Pa} \]
\[ P = 421106\ \text{Pa} \]

So, the absolute pressure at the bottom of the lake is 421106 Pa.

---

(b) What force is exerted by the water on the window of an underwater vehicle at this depth if the window is circular and has a diameter of 33.0 cm?

**Original User Response:**
\[ 143995.51\ \text{N} \]
**Feedback:**
Your response differs from the correct answer by more than 100%.

**Detailed Explanation and Solution:**

To calculate the force exerted on the window, we need to use the formula:
\[ F = P \times A \]
where:
- \( F \) is the force exerted,
- \( P \) is the pressure at depth (calculated as 421106 Pa),
- \( A \) is the area of the circular window.

First,
Transcribed Image Text:### Example Problem: Pressure and Force at Depth **Problem Statement:** (a) Calculate the absolute pressure at the bottom of a freshwater lake at a depth of 32.6 meters. Assume the density of water is 1.00 × 10³ kg/m³ and the air above is at a pressure of 101.3 kPa. **Answer:** \[ 421106\ \text{Pa} \] **Detailed Explanation and Solution:** The absolute pressure at a certain depth underwater can be calculated using the formula: \[ P = P_0 + \rho g h \] where: - \( P \) is the absolute pressure at depth, - \( P_0 \) is the atmospheric pressure at the surface (101.3 kPa or 101300 Pa), - \( \rho \) is the density of the water (1.00 × 10³ kg/m³), - \( g \) is the acceleration due to gravity (9.81 m/s²), - \( h \) is the depth of the water (32.6 m). Using the given values in the formula: \[ P = 101300\ \text{Pa} + (1.00 \times 10^3\ \text{kg/m}^3 \times 9.81\ \text{m/s}^2 \times 32.6\ \text{m}) \] \[ P = 101300\ \text{Pa} + 319806\ \text{Pa} \] \[ P = 421106\ \text{Pa} \] So, the absolute pressure at the bottom of the lake is 421106 Pa. --- (b) What force is exerted by the water on the window of an underwater vehicle at this depth if the window is circular and has a diameter of 33.0 cm? **Original User Response:** \[ 143995.51\ \text{N} \] **Feedback:** Your response differs from the correct answer by more than 100%. **Detailed Explanation and Solution:** To calculate the force exerted on the window, we need to use the formula: \[ F = P \times A \] where: - \( F \) is the force exerted, - \( P \) is the pressure at depth (calculated as 421106 Pa), - \( A \) is the area of the circular window. First,
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