A cable is attached to a 2.20 kg block A, is looped over a fixed peg at C, and is attached to plate B.(Figure 1) The coefficient of static friction between the plate and the block is μA= 0.180, the coefficient of static friction between the plate and the inclined plane is μB = 0.380, and the coefficient of static friction between the cable and the peg is μC= 0.450. If the plane's angle is 30.0 degrees, what is the maximum mass that plate B can have such that it does not slide down the plane? **Frictional Forces on Flat Belts****Learning Goal:**To be able to analyze the equilibrium of systems subjected to frictional forces at belts and surfaces.When engineers design belt drives and band brakes, they engineer them to withstand the frictional forces that develop between the belts or bands and their contacting surfaces. These frictional forces lead to tensions on each side of the contacting surfaces that are unequal; the segment aligning with the motion of the belt or band has a greater tension.**Figure:**This diagram illustrates a cable attached to a 2.20 kg block labeled as A, looping over a fixed peg at C, and extending to a plate labeled B. The system is on an inclined plane.**Part A:**A cable is attached to a 2.20 kg block A, is looped over a fixed peg at C, and is attached to plate B. The coefficient of static friction between the plate and the block is μₐ = 0.180, the coefficient of static friction between the plate and the inclined plane is μᵦ = 0.380, and the coefficient of static friction between the cable and the peg is μc = 0.450. If the plane's angle is 30.0 degrees, what is the maximum mass that plate B can have such that it does not slide down the plane?Express your answer numerically in kilograms to three significant figures.**Input:**mₐ = [6.242] kg**Status:**Incorrect; Try Again; 3 attempts remaining

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Answered: A cable is attached to a 2.20 kg block…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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A cable is attached to a 2.20 kg block A, is looped over a fixed peg at C, and is attached to plate B.(Figure 1) The coefficient of static friction between the plate and the block is μA= 0.180, the coefficient of static friction between the plate and the inclined plane is μB = 0.380, and the coefficient of static friction between the cable and the peg is μC= 0.450. If the plane's angle is 30.0 degrees, what is the maximum mass that plate B can have such that it does not slide down the plane?

**Frictional Forces on Flat Belts**

**Learning Goal:**
To be able to analyze the equilibrium of systems subjected to frictional forces at belts and surfaces.

When engineers design belt drives and band brakes, they engineer them to withstand the frictional forces that develop between the belts or bands and their contacting surfaces. These frictional forces lead to tensions on each side of the contacting surfaces that are unequal; the segment aligning with the motion of the belt or band has a greater tension.

**Figure:**
This diagram illustrates a cable attached to a 2.20 kg block labeled as A, looping over a fixed peg at C, and extending to a plate labeled B. The system is on an inclined plane.

**Part A:**
A cable is attached to a 2.20 kg block A, is looped over a fixed peg at C, and is attached to plate B. The coefficient of static friction between the plate and the block is μₐ = 0.180, the coefficient of static friction between the plate and the inclined plane is μᵦ = 0.380, and the coefficient of static friction between the cable and the peg is μc = 0.450. If the plane's angle is 30.0 degrees, what is the maximum mass that plate B can have such that it does not slide down the plane?

Express your answer numerically in kilograms to three significant figures.

**Input:**
mₐ = [6.242] kg

**Status:**
Incorrect; Try Again; 3 attempts remaining

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