A cable 300 m long weighs 600N. The tension at the emds of the cable are 400 N and 446 N, respectively. (Note: Treat this as catenary). a) Determine the difference in elevation of the supports at both ends. b) Determine the difference in elevation of the lowest point and the lower support. c) Compute the horizontal span of the cable. TI= 446 N Tz= 400 N 92 X2 L.
A cable 300 m long weighs 600N. The tension at the emds of the cable are 400 N and 446 N, respectively. (Note: Treat this as catenary). a) Determine the difference in elevation of the supports at both ends. b) Determine the difference in elevation of the lowest point and the lower support. c) Compute the horizontal span of the cable. TI= 446 N Tz= 400 N 92 X2 L.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:2. A cable 300 m long weighs 600N. The tension at the ends of the cable are 400 N
and 446 N, respectively. (Note: Treat this as catenary).
a) Determine the difference in elevation of the supports at both ends.
b) Determine the difference in elevation of the lowest point and the lower
support
c) Compute the horizontal span of the cable.
TI 446N
Tz= 400 N
92
X2
L.
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