A cab driver heads south with a steady speed of V₁ = 20.0 m/s for t₁ = 3.00 min, then makes a right turn and travels at V₂ = 25.0 m/s for t₂ = 2.00 min, and then drives northwest at v3 = 30.0 m/s for t3 = 1.00 min. For this 6.00-min trip, calculate the following. Assume +x is in the eastward direction.(a) total vector displacement (Enter the magnitude in m and the direction in degrees south of west.)magnitudedirectionFor each straight-line movement, model the car as a particle under constant velocity, and draw a diagram of the displacements, labeling the distances and angles. Let the starting point be the origin of your coordinate system. Use the relationship speed = distance/time to find the distavector, and calculate its magnitude and direction. Don't forget to convert min to s! m• south of west(b) average speed (in m/s)m/s(c) average velocity (Enter the magnitude in m/s and the direction in degrees south of west.)magnitudeXThe average velocity is the total displacement divided by the total time. Use your result from part (a) for the displacement. m/s° south of westdirection

moving south with velocity v1=20 m/s for t1=3.0 minthen turn right and moving with v2=25 m/s for…

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