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(a) (c)= dx (c) & √(x²). (e) d [ƒ(g(x))]= (g) (sin x)= dx (i) --(tan x) = dx d (k) (sec x) = dx (m) — (e²) = d (0) = (logax) = . dx d (9) (sin ¹x) = dx (b)(x) (ª) — [ƒ(x) · g(x)]- dx (f) d[f(x)] dx g(x) d (h) (cos.x) - dx d (j) (csc x) = dx d (1)(cot x) = = dx d (n) (Inx)= dx (p) & (a*) =. dx (r) & (tan¯¹x) = dx

(a) (c)= dx (c) & √(x²). (e) d [ƒ(g(x))]= (g) (sin x)= dx (i) --(tan x) = dx d (k) (sec x) = dx (m) — (e²) = d (0) = (logax) = . dx d (9) (sin ¹x) = dx (b)(x) (ª) — [ƒ(x) · g(x)]- dx (f) d[f(x)] dx g(x) d (h) (cos.x) - dx d (j) (csc x) = dx d (1)(cot x) = = dx d (n) (Inx)= dx (p) & (a*) =. dx (r) & (tan¯¹x) = dx

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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(a) d dx - (c) = d (c) = (x²)- = dx (e) — [ƒ(g(x))] = dx d dx d dx (sin x) = = (i) (tan x) = (k) d (secx) = dx (m) =(e^) = dx d (0) a (logax) = dx d (9) — (sin¯¹x) = dx (b) (d) [f(x)-g(x)]- dx (f) d dx (h) d| f(x) dx g(x) d dx (cos x) = d (1) / (csc x) = dx (1) a (cot x) = = dx (n) (In x) = dx d (p) & (a² dx (ax) = d (r) & (tan¯¹x) = dx
Transcribed Image Text:(a) d dx - (c) = d (c) = (x²)- = dx (e) — [ƒ(g(x))] = dx d dx d dx (sin x) = = (i) (tan x) = (k) d (secx) = dx (m) =(e^) = dx d (0) a (logax) = dx d (9) — (sin¯¹x) = dx (b) (d) [f(x)-g(x)]- dx (f) d dx (h) d| f(x) dx g(x) d dx (cos x) = d (1) / (csc x) = dx (1) a (cot x) = = dx (n) (In x) = dx d (p) & (a² dx (ax) = d (r) & (tan¯¹x) = dx
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