A businessman is considering investing in a small business. A random sample of 32 companies revealed that the mean was 6.5% of return and the standard deviation was 1.8%. Do the data support that the return is less than 7% at a significance level α=0.03;0.04;0.05;0.07;0.08? Use P-value.
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A businessman is considering investing in a small business. A random sample of 32
companies revealed that the mean was 6.5% of return and the standard deviation was
1.8%. Do the data support that the return is less than 7% at a significance level
α=0.03;0.04;0.05;0.07;0.08? Use P-value.
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- The distribution of hearts within a fair deck of cards would follow the __________. Multiple Choice Normal distribution Level distribution Uniform distribution Poisson distributionIn a test of the effectiveness of garlic for lowering cholesterol, 64 subjects were treated with raw garlic. Cholesterol levels were measured before and after the treatment. The changes (before minus after) in their levels of LDL cholesterol (in mg/dL) have a mean of 0.4 and a standard deviation of 23.9. Use a 0.05 significance level to test the claim that with garlic treatment, the mean change in LDL cholesterol is greater than 0. What do the results suggest about the effectiveness of the garlic treatment? Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. What are the null and alternative hypotheses? Ο Α. Ho: μ=0 mg/ldL H1: µ > 0 mg/dL B. Ho : μ=0 mg/dL H1: µ0 mg/dL H1: µ<0 mg/dL D. Ho: µ=0 mg/dL H1:µ#0 mg/dLThe mean number of English courses taken in a two-year time period by male and female college students is believed to be about the same. An experiment is conducted and data are collected from 29 males and 16 females. The males took an average of three English courses with a standard deviation of 0.8. The females took an average of four English courses with a standard deviation of 1.0. Are the means statistically the same? (Assume a 5% level of significance.)
- According to Management Accounting, salary figures for certified management accountants (CMAs) who are in the field less than 1 year are normally distributed with a mean of $31,129. A random sample of 15 first year CMAs in Denver produces a mean salary of $32,279, with a standard deviation of $1,797. Test the hypothesis that the mean for all Denver first year CMAs is not equal to 31,129. Use the .05 level of significance. State the null hypothesis H0: _____________ State the alternative hypothesis H1: _____________ What is the test statistic used for the test (z or t) and its value (round to 2 places) State the significance or alpha (α) level Determine the p-value. (round to 4 places) Do you or do you not reject the null hypothesis? Why? Write a clear conclusion using a complete sentence.A public bus company official claims that the mean waiting time for Bus # 14 during peak hours is approximately 10 minutes. Karen took Bus # 14 during peak hours on 36 different occasions. Her mean waiting time was 8.7 minutes. Assume that the population standard deviation o of 2.9 minutes is known. At the 0.01 significance level, test if the mean of all the peak hours waiting time for Bus # 14 is significantly different from 10 minutes.In a school district, all sixth grade students take the same standardized test. The superintendant of the school district takes a random sample of 3030 scores from all of the students who took the test. She sees that the mean score is 169169 with a standard deviation of 7.06747.0674. The superintendant wants to know if the standard deviation has changed this year. Previously, the population standard deviation was 1313. Is there evidence that the standard deviation of test scores has decreased at the α=0.005α=0.005 level? Assume the population is normally distributed. Step 1 of 5: State the null and alternative hypotheses. Round to four decimal places when necessary. Step 2 of 5: Determine the critical value(s) of the test statistic. If the test is two-tailed, separate the values with a comma. Round your answer to three decimal places. Step 3 of 5: Determine the value of the test statistic. Round your answer to three decimal places. Step 4 of 5: Make the…
- In a test of the effectiveness of garlic for lowering cholesterol, 64 subjects were treated with raw garlic. Cholesterol levels were measured before and after the treatment. The changes (before minus after) in their levels of LDL cholesterol (in mg/dL) have a mean of 0.6 and a standard deviation of 1.92. Use a 0.05 significance level to test the claim that with garlic treatment, the mean change in LDL cholesterol is greater than 0. What do the results suggest about the effectiveness of the garlic treatment? Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. What are the null and alternative hypotheses?Help............
- In a test of the effectiveness of garlic for lowering cholesterol, 36 subjects were treated with raw garlic. Cholesterol levels were measured before and after the treatment. The changes (before minus after) in their levels of LDL cholesterol (in mg/dL) have a mean of 0.8 and a standard deviation of 24.1. Use a 0.05 significance level to test the claim that with garlic treatment, the mean change in LDL cholesterol is greater than 0. What do the results suggest about the effectiveness of the garlic treatment? Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. ..... What are the null and alternative hypotheses? 'A. H : μ-0 mgldL B. H0 μ> 0 mg/dL H;: u> 0 mg/dL H: µ< 0 mg/dL O C. Ho: µ= 0 mg/dL O D. Ho: H=0 mg/dL H1: µ#0 mg/dL H,: µ<0 mg/dL Determine the test statistic. (Round to two decimal places as needed.)In a random sample of 6 cell phones, the mean full retail price was 517.30 and standard deviation is 184.00. Further research suggests that the population mean is 425.73. Does the t-value for the original sample fall between -t0.99 and t0.99?The 2013 general Social Survey asked a large number of people how much time they spent watching TV each day. The mean number of hours was 3.7 with a standard deviation of 2.5. Assume that in a sample of 57 teenagers, the sample standard deviation of daily TV time is 2.2 hours, and that the population of TV watching times is normally distributed. Under 1% significance level can you conclude that the population standard deviation of TV watching times for teenagers is different from 2.5? Procedure: One variance x² Hypothesis Test v Assumptions: (select everything that applies) ✔Population standard deviation is unknown ✔Simple random sample Normal population Sample size is greater than 30 0° The number of positive and negative responses are both greater than 10 Population standard deviation is known Step 1. Hypotheses Set-Up: Ho: Select an answer Ha: Select an answer ✓ ? V Step 2. The significance level a = OT % where? is the Select an answer ? " Part 2 of 5 and the units are and the test…