A bullet of mass m bounces off a heavy block with mass M and change its direction of motion by angle 0 and changing its velocity magnitude from 2v, to v,. Find velocity of the block M right after the collision, assuming the block originally was at rest on frictionless surface
A bullet of mass m bounces off a heavy block with mass M and change its direction of motion by angle 0 and changing its velocity magnitude from 2v, to v,. Find velocity of the block M right after the collision, assuming the block originally was at rest on frictionless surface
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![A bullet of mass m bounces off a heavy block with mass M
and change its direction of motion by angle 0 and changing
its velocity magnitude from 2v, to v,. Find velocity of the
block M right after the collision, assuming the block originally
was at rest on frictionless surface](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3226dc49-26d3-48ff-b18a-24c6372a68f4%2Fa8168399-9e6b-4e7c-af31-7e0732a6fade%2Fqsh93g3.png&w=3840&q=75)
Transcribed Image Text:A bullet of mass m bounces off a heavy block with mass M
and change its direction of motion by angle 0 and changing
its velocity magnitude from 2v, to v,. Find velocity of the
block M right after the collision, assuming the block originally
was at rest on frictionless surface
Expert Solution
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Step 1
![mass of bulle t cmil =m
mass of block (mz) = M
Velocity of bullet (u) = 20oi
of block before collisson (uz) =o
Velooity
Velocity of bullet after collision (V) = Vo coso i + Vo sin@j
Velocity of block aften collision (Vz)= ?
+ dg sim@ j](https://content.bartleby.com/qna-images/answer/3226dc49-26d3-48ff-b18a-24c6372a68f4/259e65c1-6577-47d5-9407-fc99ffb75b2d/of81aon.png)
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