A bullet of mass m bounces off a heavy block with mass M and change its direction of motion by angle 0 and changing its velocity magnitude from 2v, to v,. Find velocity of the block M right after the collision, assuming the block originally was at rest on frictionless surface

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A bullet of mass m bounces off a heavy block with mass M
and change its direction of motion by angle 0 and changing
its velocity magnitude from 2v, to v,. Find velocity of the
block M right after the collision, assuming the block originally
was at rest on frictionless surface
Transcribed Image Text:A bullet of mass m bounces off a heavy block with mass M and change its direction of motion by angle 0 and changing its velocity magnitude from 2v, to v,. Find velocity of the block M right after the collision, assuming the block originally was at rest on frictionless surface
Expert Solution
Step 1
mass of bulle t cmil =m
mass of block (mz) = M
Velocity of bullet (u) = 20oi
of block before collisson (uz) =o
Velooity
Velocity of bullet after collision (V) = Vo coso i + Vo sin@j
Velocity of block aften collision (Vz)= ?
+ dg sim@ j
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