A bullet of mass m = 5.00 g moves directly upward at a speed of v= 200 m/s. It strikes and lodges in the center of a block of mass M= 60.0 g initially at rest on a table. To what maximum height does the block/bullet combination then rise above the table? A)h = 12.1 m B) h=14.2 m C) h = 48.3 m D) h = 82.7 m E) h=157 m Bullet

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Chapter8: Momentum And Collisions
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PHYS2001 Fall ...
A) h= 12.1 m
B) h=14.2 m
C) h = 48.3 m
D) h = 82.7 m
E) h=157 m
3 / 5
A bullet of mass m = 5.00 g moves directly upward at a speed of v= 200 m/s. It strikes
and lodges in the center of a block of mass M= 60.0 g initially at rest on a table. To what
maximum height does the block/bullet combination then rise above the table?
100% +
A) L = 0.30 m
B) L = 0.50 m
C) L = 1.1 m
D) L = 1.8 m
E) L=2.0 m
Beginning from rest, a block of mass m slides down a frictionless curve. After sliding
downward by h = 0.60 m, the block encounters horizontal concrete and slides to a stop.
The coefficient of kinetic friction between the block and the concrete is μ = 0.30. What
is the stopping distance L?
Bullet
h
L
Transcribed Image Text:PHYS2001 Fall ... A) h= 12.1 m B) h=14.2 m C) h = 48.3 m D) h = 82.7 m E) h=157 m 3 / 5 A bullet of mass m = 5.00 g moves directly upward at a speed of v= 200 m/s. It strikes and lodges in the center of a block of mass M= 60.0 g initially at rest on a table. To what maximum height does the block/bullet combination then rise above the table? 100% + A) L = 0.30 m B) L = 0.50 m C) L = 1.1 m D) L = 1.8 m E) L=2.0 m Beginning from rest, a block of mass m slides down a frictionless curve. After sliding downward by h = 0.60 m, the block encounters horizontal concrete and slides to a stop. The coefficient of kinetic friction between the block and the concrete is μ = 0.30. What is the stopping distance L? Bullet h L
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